The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.
Answer:
40·919 m
Explanation:
Initial velocity of the arrow = 46 m/s
Angle at which it is thrown from horizontal = 38°
<h3>At the maximum height, the vertical component of velocity will be 0</h3>
Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s
From the formula
<h3>v² - u² = 2 × a × s</h3>
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
Considering the formula in vertical direction and taking upward direction as positive
v = 0
u = 28·32 m/s
a = - g = - 9·8 m/s²
Let s be the maximum height
- 28·32² = - 2 × 9.8 × s
⇒ s = 40·919 m
∴ The arrow will go 40·919 m high
Call the capacitance C.
<span>Note the energy in a capacitor with voltage V is E =½CV². </span>
<span>Initial energy = ½C(12)² = 72C </span>
<span>40% of energy is delivered, so 60% remains.in the capacitor. </span>
<span>Remaining energy = (60/100) x 72C =43.2C </span>
<span>If the final potential difference is X, the energy stored is ½CX² </span>
<span>½CX² = 43.2C </span>
<span>X² = 2 x 43.2 = 86.4 </span>
<span>X = 9.3V</span>
Answer:6m/s^2
Explanation:
Mass =3kg
Force=18N
Acceleration =force ➗ mass
Acceleration =18 ➗ 3
Acceleration =6
Acceleration =6m/s^2
