Answer:
<em>The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total momentum of a system of bodies is conserved unless an external force is applied. The formula for the momentum of a body with mass m and velocity v is:
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all

If a collision occurs, the velocities change to v' and the final momentum is:

In a system of two masses, the law of conservation of linear momentum is:

According to the conditions of the problem, two persons standing on a frictionless surface are initially at rest (v1=0, v2=0). Their masses are m1=50 Kg and m2=65 Kg. After the push, one person (say m1) moves backward at v1'=-1.1 m/s. We can calculate the speed of the other person by solving for v2':

Substituting:



The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.