Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e. 
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-
b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :
Answer:
Infinitely many triangles.
Step-by-step explanation:
Given the lengths of two sides are 8 inches and 10 inches.
Let's assume third side = x inches.
Using the Triangle Inequalities given as follows:-
1. a+b > c,
2. b+c > a,
3. c+a > b.
Using the lengths given in the problem, we can write:-
1. x+8 > 10 ⇔ x > 10-8 ⇔ x > 2.
2. x+10 > 8 ⇔ x > 8-10 ⇔ x > -2.
3. 8+10 > x ⇔ x < 18.
So, the solution set is 2 < x < 18. It means third side can take any value in interval (2, 18).
Hence, there are infinitely many triangles.
M2 would be (3x-54) just like m5
Answer:
When the line of the graph is going up
Step-by-step explanation:
When the line is going down that means its a exponential decay :)
1:3 :) why? well if we think about it 2:9 is just not gonna work, cross that out. 3:18? no, thanks. 1:3 is it
