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Irina-Kira [14]
2 years ago
12

Int he figure below find AC

Mathematics
1 answer:
Ahat [919]2 years ago
7 0

Given :-

  • Two triangles with their two angles equal .

To Find :-

  • Measure of AC .

Answer :-

Here in ∆ABC and ∆EDC ,

  • \angle CAB = \angleCED (given )
  • \angle CBA = \angleCDE (given)

Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

→ AC/EC = BC/DC

→ AC/9 = 8/12

→ AC = 8/12 * 9

→ AC = 6

<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>

I hope this helps.

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Which statement is true about the sum of (5y/y^2)+(y-4/5y) ? A: The denominator of the simplified sum is y2 + 5y. B: The denomin
lora16 [44]

Answer:

Dude the answer is B

Step-by-step explanation:

7 0
3 years ago
Explain howto use friendly percents to find 35% of 80
elena-14-01-66 [18.8K]

Answer:

28

Step-by-step explanation:

35% × 80 =

(35 ÷ 100) × 80 =

(35 × 80) ÷ 100 =

2,800 ÷ 100 =

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I hope this helps :)

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3 years ago
if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

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3 years ago
what is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 48 degrees?
Vladimir79 [104]
180-2\cdot48=180-96=84
7 0
3 years ago
I need help again.lol
Monica [59]

Answer:

13\ units

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

Where ((x_1,y_1)) and ((x_2,y_2)) are the points which one needs to find the distance between. In this case, these points are as follows:

k\ (-3,5)

j\ (-8, -7)

Substitute these points into the formula and solve for the distance between these points,

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

Simplify,

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

D=\sqrt{(-3+8)^2+(5+7)^2

D=\sqrt{(5)^2+(12)^2

D=\sqrt{25+144}

D=\sqrt{169}

D=13

8 0
2 years ago
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