I think the correct answer from the choices listed above is the second option. If a copper atom loses two electrons, the name of the copper ion is copper (II) ion . Also it is called cupric acid. However, the latter <span>is an old term and is not recommended. Hope this answers the question.</span>
<span>moles glucose = 19 g / 180 g/mol= 0.105
M = 0.105 / 0.100 L = 1.05
moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216
New concentration = 0.0216 /0.500 L = 0.0432 M
moles in 100 mL = 0.100 L x 0.0432 = 0.00432
mass = 0.00432 x 180 g/mol= 0.778 g</span>
Answer:
6.6666666667 feet per second I believe
<h3>
Answer:</h3>
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
<h3>
Explanation:</h3>
- Assuming the reaction is the reduction of CuO by H₂
- Then the balanced equation for the reaction is;
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
- The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
- The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.
- In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.