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Mamont248 [21]
3 years ago
6

How can you convert diamond into graphite ?​

Chemistry
2 answers:
Setler79 [48]3 years ago
4 0

Answer:

<em>➢</em><em>There are different ways to trigger the conversion of diamond to graphite, for instance by simply heating the diamond under exclusion of oxygen or even with an aimed mechanical stroke.</em>

Explanation:

<em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em> have</em><em> a</em><em> great</em><em> day</em><em> bye</em><em> and</em><em> Mark</em><em> brainlist</em><em> if</em><em> the</em><em> answer</em><em> is</em><em> correct</em>

<em>kai6417</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on </em><em>learning</em>

Alexxx [7]3 years ago
3 0
By using ultra-short flashes of an x-ray laser
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‼️ i really need help. if anyone can do 10 pages of a grade 11 chemistry packet (multiple choice) let me know. i can pay money
Alja [10]

Answer:

mmmmmmmmmmmmmmmmmm

Explanation:

6 0
3 years ago
Old thermometers contained very small amounts of mercury. The mercury in the photo has a melting point of -38.8 degrees Celsius.
Nikolay [14]

Answer:

••It's melting point equals -38.8 degrees Celsius because it is mercury. |••

Explanation:

This one makes the most sense out of the answers.

7 0
3 years ago
How many atoms are in 57.5 liters of xenon gas at STP
TiliK225 [7]

Answer:

1.55 × 10²⁴ atoms Xe

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 57.5 L Xe at STP

[Solve] atoms Xe

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe

4 0
3 years ago
What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
steposvetlana [31]
STP condition mean we have P=1 atm. T=273K. R=ideal gas constant, but make sure you use the one that has the same units of pressure, temperature that you are using. In this case R=0.0821 L*atm K^-1mol^1. You are provided with n=2.1 moles.
V=nRTP
Input your values and solve.
3 0
3 years ago
Which of these careers would a student studying biotechnology
matrenka [14]
I think it’s c I could be wrong
3 0
3 years ago
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