1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vesna_86 [32]
3 years ago
6

Copper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f

= 6.3 × 10 10 Calculate the solubility (in g·L−1) of CuBr ( s ) ( K sp = 6.3 × 10 − 9 ) in 0.76 M NH 3 ( aq ) .
Chemistry
1 answer:
Kruka [31]3 years ago
4 0

Answer:

53.18 gL⁻¹

Explanation:

Given that:

Cu^{2+}_{(aq)} + 2NH_{3(aq)} ------>  [Cu(NH_3)_2]^+_{(aq)}      ------equation (1)

where;

Formation Constant  (k_f) = 6.3*10^{10}

However, the Dissociation of CuBr_{(s) yields:

CuBr_{(s)}      ⇄    Cu^{+}_{(aq)}  + Br^-_{(aq)}      -------------- equation (2)

where;

the Solubility Constant (k_{sp})  = 6.3 *10^{-9

From equation (1);

(k_f) = \frac{[[Cu(NH_3)_2]^+]}{[Cu^{2+}][NH_3]^{2}}            ---------  equation (3)

From equation (2)

(k_{sp})  = [Cu^+][Br^-]           ---------  equation (4)

In NH_3, the net reaction for CuBr_{(s) can be illustrated as:

CuBr_{(s)   + 2NH_{3(aq)}  ⇄  [Cu(NH_3)_2]^+_{(aq)}  + Br^-_{(aq)}

The equilibrium constant (K) can be written as :

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}

If we multiply both the numerator and the denominator with  [Cu^+] ; we have:

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}*\frac{[Cu^+]}{[Cu^+]}

K=\frac{[[Cu(NH_3)_2]^+}{[NH_3]^2[Cu^+]}*{[Cu^+][Br^-]}

K = k_f *k_{sp}

K= (6.3*10^{10})*(6.3*10^{-9})

K= 3.97*10^2

K ≅ 4.0*10^2

Now; we can re-write our equilibrium constant again as:

K=\frac{[[Cu(NH_3)_2]^+][Br^-]}{[NH_3]^2}

4.0*10^2 = \frac{(x)(x)}{(0.76-2x)^2}

4.0*10^2 = \frac{(x)^2}{(0.76-2x)^2}

4.0*10^2 = (\frac{(x)}{(0.76-2x)})^2

By finding the square of both sides, we have

\sqrt {4.0*10^2} = \sqrt {(\frac{(x)}{(0.76-2x)})^2

2.0*10 = \frac{x}{(0.76-2x)}

20(0.76-2x) =x

15.2 -40x=x

15.2 = 40x +x

15.2 = 41x

x = \frac{15.2}{41}

x = 0.3707 M

In gL⁻¹; the solubility of CuBr_{(s) in 0.76 M NH_3 solution will be:

= \frac{0.3707 mole of CuBr}{1L}*\frac{143.45 g}{mole of CuBr}

=  53.18 gL⁻¹

You might be interested in
2B + 3H2 2BH3<br> How many moles of BH3 are synthesized when 27.0 moles of H2 completely react?
densk [106]

Answer:

fa o poză te rog frumos ca nu stiu ce ex este

3 0
3 years ago
How many liters of 1.5 M potassium permanganate could be made if 152 g of the solute are available?
Misha Larkins [42]

Answer:

0.64 L

Explanation:

Recall that

n= CV where n=m/M

Hence:

m/M= CV

m= given mass of solute =152g

M= molar mass of solute

C= concentration of solute in molL-1 = 1.5M

V= volume of solute =????

Molar mass of potassium permanganate= 158.034 g/mol

Thus;

152 g/158.034 gmol-1= 1.5M × V

V= 0.96/1.5

V= 0.64 L

6 0
3 years ago
Read 2 more answers
In addition to not causing damage to the sample, what is another advantage of using a microspectrophotometer to analyze fibers?
Tems11 [23]

Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

<h3>What is a microspectrophotometer?</h3>

Microspectrophotometry is a biological technique used to measure the absorption or transmission spectrum of a solid or liquid material in either transmitted or reflected light.

Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.

One advantage of microspectrophotometry is that the sample does not get damaged. However,

However, another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

Learn more about microspectrophotometry at: brainly.com/question/5832827

5 0
2 years ago
Is soda an acid or a base
Aneli [31]

Answer:

It's an Acid

Explanation:

cuz of the Co2 and it's naturally acidic nature

4 0
3 years ago
What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E
yulyashka [42]

Answer: K_2SO_3.

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K=\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = \frac{1.23}{0.63}=2

For S =\frac{0.63}{0.63}=1

For O =\frac{1.89}{0.63}=3

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is K_2SO_3.

7 0
3 years ago
Other questions:
  • Could someone please help on just question 2?
    8·1 answer
  • In caves, dripping groundwater containing calcium bicarbonate can form stalactites and stalagmites. When the water is exposed to
    8·1 answer
  • Why do people use symbols and numbers instead of equations in chemistry?
    14·1 answer
  • Define: Law of Definite Proportion
    7·1 answer
  • So my chem experiment asks us: What is the molarity of a 6.0 ppm solution (it's a 6.0 ppm chlorophyll solution, hexane is the so
    13·2 answers
  • C. Which molecule is not linear?<br> a H₂O<br> b. CO₂<br> c. N₂<br> d. Cl₂
    9·1 answer
  • PLZ HELP ME. I NEED ANSWER ASAP!!!!!!
    11·1 answer
  • What do we use to keep track of major Earth events?​
    13·1 answer
  • D<br><br>saddddddasdasdwaefsdf
    8·1 answer
  • Choose the formula for hydroxide.<br> OH<br> HPO4<br> Ca(OH)2<br> d Ba(OH)2
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!