Answer:
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Answer:
267.14 iron oxide.
Explanation:
Given that
We know that molecular mass of iron-oxide = 160 g/mole.
We know that molecular mass of iron = 56 g/mole.
From the above reaction we can say that
1 mole of iron -oxide produce 2 mole of iron
160 gm of iron oxide produce 112 gm of iron
So
1 gm of iron required of iron oxide
Therefore
187 gm of iron required of iron oxide.
Therefore 187 gm of iron required 267.14 iron oxide.
Answer:
Explanation:
The given equation is not correctly balanced. However the number of each type of atoms on right side are,
Mg = one magnesium atom
S = two sulfur atom
Cu = two cuppor atoms
Cl = two chlorine atoms
Chemical equation.
MgS + CuCl₂ → CuS + MgCl₂
Balance chemical equation:
2MgS(aq) + 2CuCl₂(aq) → 2CuS(s) + 2MgCl₂(aq)
In case of balance chemical equation number of each type of atoms on right side are,
Mg = two magnesium atom
S = two sulfur atom
Cu = two cuppor atoms
Cl = four chlorine atoms (because two chlorine atom form one chlorine molecule)
The answer is electrolytes. Strong electrolytes like strong acids, strong bases and salts dissociate completely into ions when dissolved and no neutral molecules are present in their solution. Weak electrolytes like weak acids and weak bases do not completely ionize in water and some neutral molecules are present in their solution, while nonelectrolytes do not dissociate into ions when in solution at all.
Answer:
Increasing pressure shifts rxn right (lower molar volume side of equation).
Explanation:
In general, if a stress is applied to a gas phase reaction, the reaction will shift away from the applied stress and establish a new equilibrium for the given reaction. The applied stress factors include ...
changes in masses of reactant or product,
changes in applied temperature values, and/or
changes in applied pressure values for a reaction confined in a reaction vessel.
For this problem, if pressure is increased on the reaction N₂(g) + 3H₂(g) ⇄ 2NH₃(g), the reaction will shift away from the applied stress, that is, in the direction of the product side of the reaction in order to relieve the applied stress as there are fewer number of moles of gas on the product side of the equation.