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kodGreya [7K]
3 years ago
14

Hi! I need help with this question, if it is possible, please answer immediately.

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

A.

Explanation:

The paper clip allows elictricity to pass, unlike the eraser or paper

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How many grams of dextrose are needed to make 725 mL of a 26.0% (w/v) dextrose solution? Note that mass is not technically the s
Diano4ka-milaya [45]

Answer:

188.5g of dextrose are needed

Explanation:

In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.

As you want to prepare 725mL of a 26.0% (w/v) solution. you need:

725mL * (26g / 100mL) = 188.5g of solute =

<h3>188.5g of dextrose are needed</h3>
3 0
3 years ago
1.25 x 1025 molecules of glucose (C H202) is<br> how many moles of glucose?
ExtremeBDS [4]

Answer:

1281.25 Moles of glucose

Explanation:

Multiply 1.25x1025= 1281.25

5 0
3 years ago
Write and balance the equation for the combustion of the fatty acid lauric acid, (C12H24O2).
Harlamova29_29 [7]

C12H24O2 +17 O2-------->12CO2 + 12H2O

<h3>Combustion:-</h3>

combustion is a chemical reaction that often involves the presence of oxygen and produces heat and light in the form of flames.

<h3>Lauric acid:-</h3>

Lauric acid has a 12-carbon backbone and is a saturated medium-chain fatty acid. In addition to being a key component of coconut oil and palm kernel oil, lauric acid occurs naturally in a variety of plant and animal fats and oils.

White solid lauric acid has a little bay oil odour to it.

Lauric acid is a cheap, non-toxic, and easy-to-handle substance that is frequently employed in lab studies on melting-point depression. Because lauric acid is a solid at ambient temperature but a liquid at boiling temperatures, it can be used to test different solutes to determine their molecular weights.

To learn more about Fatty acids refer to :-

brainly.com/question/26353151

#SPJ10

4 0
2 years ago
If you increase the temperature of a reaction, then the reaction rate will ...
DIA [1.3K]
The answer is B.Increase
6 0
3 years ago
A chemist prepares a solution of mercury(I) chloride Hg2Cl2 by measuring out
Genrish500 [490]

Answer:

1.26 × 10^-8 M

Explanation:

We are given;

Number of moles of mercury (i) chloride as 0.000126 μmol

Volume is 100 mL

We are required to calculate the concentration of the solution.

We need to know that;

Concentration is also known as molarity is given by;

Molarity = Number of moles ÷ Volume

Number of moles = 1.26 × 10^-10 Moles

Volume = 0.01 L

Therefore;

Concentration = 1.26 × 10^-10 Moles ÷ 0.01 L

                       = 1.26 × 10^-8 M

Thus, the molarity of the solution is 1.26 × 10^-8 M

6 0
3 years ago
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