Answer:
The relative humidity is 36%.
Explanation:
Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.
![Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }](https://tex.z-dn.net/?f=Relative%20humidity%3D%5Cfrac%7B%28e_%7Bw%7D-%5BN%2A%281%2B0.00115%2AT_%7Bw%7D%2A%28T_%7Bd%7D-T_%7Bw%7D%29%29%5D%29%2A100%7D%7Be_%7Bd%7D%20%7D)
Also,
![e_{d}=6.112*e^{[\frac{(17.502*T_{d} )}{(240.97+T_{d} )}]}](https://tex.z-dn.net/?f=e_%7Bd%7D%3D6.112%2Ae%5E%7B%5B%5Cfrac%7B%2817.502%2AT_%7Bd%7D%20%29%7D%7B%28240.97%2BT_%7Bd%7D%20%29%7D%5D%7D)
And,
![e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}](https://tex.z-dn.net/?f=e_%7Bw%7D%3D6.112%2Ae%5E%7B%5B%5Cfrac%7B%2817.502%2AT_%7Bw%7D%20%29%7D%7B%28240.97%2BT_%7Bw%7D%20%29%7D%5D%7D)
Here e =2.718, 
and 
are the temperature at dry bulb and wet bulb temperatures, respectively.
So, the relative humidity after substituting the values of Td = 2 C and Tw = -2 C is 36%.
Answer:0.125 moles of CaCl2
Option D 0.13moles
Explanation:
Molarity= number of moles/ volume of solution
0.25M×.5 = number of moles
0.125 moles
3 Particles
Inside the Nucleus:
Protons = +1 relative charge, relative mass of 1.
Neutrons = 0 relative charge, relative mass of 1.
Outside of Nucleus (On on shells):
Electrons = -1 relative charge, relative mass of 0.0005.
Atoms are neutral since there is always the same number of protons as electrons, so the charges cancel each other out.
Answer:
The vinegar is highly acidic by 100 times than yogurt.
Explanation:
∵ pH = -log[H⁺]
- The concentration of H⁺ in yogurt:
∵ pH = -log[H⁺]
∴ 5 = -log[H⁺]
∴ [H⁺] = 1.0 x 10⁻⁵ M.
- The concentration of H⁺ in vinegar:
∵ pH = -log[H⁺]
∴ 3 = -log[H⁺]
∴ [H⁺] = 1.0 x 10⁻³ M.
the ratio of H⁺ in vinegar to that in yogurt = 1.0 x 10⁻³ M / 1.0 x 10⁻⁵ M = 100.0.
<em>∴ The vinegar is highly acidic by 100 times than yogurt.</em>
<em></em>
Answer:
The equilibrium partial pressure of O2 is 0.545 atm
Explanation:
Step 1: Data given
Partial pressure of SO2 = 0.409 atm
Partial pressure of O2 = 0.601 atm
At equilibrium, the partial pressure of SO2 was 0.297 atm.
Step 2: The balanced equation
2SO2 + O2 ⇆ 2SO3
Step 3: The initial pressure
pSO2 = 0.409 atm
pO2 = 0.601 atm
pSO3 = 0 atm
Step 4: Calculate the pressure at the equilibrium
pSO2 = 0.409 - 2X atm
pO2 = 0.601 - X atm
pSO3 = 2X
pSO2 = 0.409 - 2X atm = 0.297
X = 0.056 atm
pO2 = 0.601 - 0.056 = 0.545 atm
pSO3 = 2*0.056 = 0.112 atm
Step 5: Calculate Kp
Kp = (pSO3)²/((pO2)*(pSO2)²)
Kp = (0.112²) / (0.545 * 0.297²)
Kp = 0.261
The equilibrium partial pressure of O2 is 0.545 atm
