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Setler79 [48]
3 years ago
6

PLEASE HELP!!

Chemistry
2 answers:
Ahat [919]3 years ago
6 0
THE ANSWER IS NH3!!!!!!! ;) your welcome
NARA [144]3 years ago
3 0
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

                              HCl  +  NH₃  →  NH₄Cl

Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
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Pls help why is it reduced
Ipatiy [6.2K]

Answer:

its orginal charge is none then through the reaction it is reduced because then final charge is -1 meaning is went down 1 so its charge was reduced

Hope this helps! :)

4 0
2 years ago
Read 2 more answers
Is hydrogen a molecule or compound
Ainat [17]
It is a molecule because hydrogen is an element.
An element is made up of molecules
7 0
3 years ago
What is the significant digit in 23.45
klio [65]
If you mean the number of Significant Figures/Digits in 23.45, it would be 4. This is because every single non-zero digit is counted as a significant figure
7 0
2 years ago
A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
Read 2 more answers
the radioisotope radon-222 has a half-life of 3.8 days. how much of a 65-g sample of radon-222 would be left after approximately
MariettaO [177]
Use the 1st order decay equation 
<span><span>Cfinal</span>=<span>Cinitial</span><span>e<span>−kt</span></span></span> 
by filling in and doing the math you will get:

<span> </span><span>Cfinal</span><span> = 1.11 grams Rn-222 after 23 days. 
 
hope this helps 

</span>
7 0
3 years ago
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