If you're familiar with the quadratic equation
well,
is the x component of the vertex, in your case, the vertex is the highest point
figure out what t is at the highest point, and then substitute that back into the equation in order to determine height
x=t in this problem
The answer in this question is B The diagonals of the parallelogram are congruent because that's only possible for right angle quadrilaterals. We can say that the diagonals of the parallelogram are congruent. The diagonals of this figures have the same size and shape.
Answer:
the solution is C. identical
Step-by-step explanation:
slope of parallel lines are the same
The radius of the circle is 3 cm.
<u>Step-by-step explanation:</u>
Refer the attached diagram, the circle with centre O. In that given, AB is tangent given as 4 cm and distance of point from the circle, OA = 5 cm
As AB is tangent, OB (radius of circle) is perpendicular to AB (tangent at any point of circle). Therefore the angle of OBA is 90 degree.
Also, triangle OAB is a right angled triangle (refer attached diagram). By using Pythagoras theorem in right angled triangle,
Substitute the given values in the above expression, we get
Taking square root on both side, we get
Radius of the circle, OB = 3 cm
