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Nostrana [21]
2 years ago
11

1) The talent competition was selling student tickets for $12 and adult tickets for $17. 145 people attended the competition. Th

e school made $2,065. How many adults attended the talent competition?
2) John is in charge of feeding the pigs and cows on the farm. The cow's food costs twice as much as the pig's food. There are 46 cows and 22 pigs on the farm. John has an $860 budget for food a month. How much can John spend on food for each cow per month?

Mathematics
1 answer:
yan [13]2 years ago
8 0
1) 65 Adults attended the talent competition.
2) Approximately $15 per cow

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iogann1982 [59]
What do you need to know bud
6 0
3 years ago
Can someone please help I asked earlier but no one is answering!
Agata [3.3K]

Answer:

So the expression would be P = 2L + 2w

Tho that's about all I know, you could try plugging in 5.5 for L and w so then it would be <em>P = 2(5.5) + 2(5.5^2)</em> But I'm not too sure, sorry about that.

Step-by-step explanation:

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3 years ago
PLEASE HELP ME I NEED THIS DONE ASAP !!!
Maurinko [17]

Answer:

20

Step-by-step explanation:

the number next to the variable is the coefficient.

20 is the coefficient, while w is the variable

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3 years ago
How do I find angles a, b, and c?
LenaWriter [7]
For angle A, you need to do 180-130 which is 50
for angle B, you need to do 180- 90 - 50 which is 40
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If you want me to explain you with further details with how exactly I got those answers and how I knew what to do, then ask me. 
6 0
3 years ago
Read 2 more answers
Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day. The
faltersainse [42]

Answer:

30units,2900

Step-by-step explanation:

Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.

The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.

If x units are produced and sold we have

Costs for x units = variable costs *x +Fixed costs = 400x+1600

Sales revenue = no of units sold * price = x(700-5x) = 700x-5x^2

Profit funciton = P(x) = Sales revenue - Total cost

= 700x-5x^2-400x-1600\\=300x-5x^2-1600

To get maximum profit we use derivative test I derivative =0 and II derivative =negative

P'(x) = 300-10x\\p"(x) = -10

Producing 30 units will maximize the profit.

Max profit

=P(30) = 2900

8 0
4 years ago
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