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Nostrana [21]
2 years ago
11

1) The talent competition was selling student tickets for $12 and adult tickets for $17. 145 people attended the competition. Th

e school made $2,065. How many adults attended the talent competition?
2) John is in charge of feeding the pigs and cows on the farm. The cow's food costs twice as much as the pig's food. There are 46 cows and 22 pigs on the farm. John has an $860 budget for food a month. How much can John spend on food for each cow per month?

Mathematics
1 answer:
yan [13]2 years ago
8 0
1) 65 Adults attended the talent competition.
2) Approximately $15 per cow

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Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

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Consider this expression.
schepotkina [342]

Answer:

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Step-by-step explanation:

Given

7m^2 + (2m - 1)(m + 9)

Required:

Simplify

We start by opening the bracket

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Collect Like Terms

9m^2 + 17m- 9

Hence, the equivalent expression is 9m^2 + 17m- 9

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answer 2 d

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