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antoniya [11.8K]

3 years ago

10

1. What is the value of x?

1 answer:

lara31 [8.8K]3 years ago

6 0

Is there any option to choose from ?

If so show them and I’ll probably be able to answer .

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Find the mode for the<br> following data set {1,3,5,7,9]<br><br> PLS HELP

kvasek [131]

Answer: There is no mode.

Step-by-step explanation:

The mode is the number in a data set that occurs most frequently. Count how many times each number occurs in the data set. The mode is the number with the highest tally. It's ok if there is more than one mode. And if all numbers occur the same number of times there is no mode.

Hope this helps!

7 0

4 years ago

If 10 minutes talk-time costs $2, how much will 7 minutes cost?

Sladkaya [172]

The answer is A) $1.40

5 0

3 years ago

Read 2 more answers

Ken's landscape gardening business creates odd-shaped lawns that include semicircles. Find the area of this semicircular section

salantis [7]

Answer:

Area of semicircular lawn is 9.82 square meter.

Step-by-step explanation:

Given:

Diameter of the semicircle = 5 m

So we will find the radius.

Radius is half of the diameter.

Radius $r=\frac{5}{2}=2.5\ m$

We need to find the area of the lawn.

Solution:

Now we know that;

Area of semicircle is half times π times square of the radius.

framing in equation form we get;

Area of semicircular lawn = $\frac12\pi r^2=\frac12\times\frac{22}{7}\times 2.5\times 2.5=9.82\ m^2$

Hence Area of semicircular lawn is 9.82 square meter.

7 0

3 years ago

a study of nickels showed that the standard deviation of the weight of nickels is 300 milligrams. A coin counter manufacture wis

cupoosta [38]

Using the z-distribution, a sample of 609 nickels has to be weighed.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

For this problem, the parameters are:

$M = 20, \sigma = 300, z = 1.645$

We solve for n to find the sample size, then:

$M = z\frac{\sigma}{\sqrt{n}}$

$20 = 1.645\frac{300}{\sqrt{n}}$

$20\sqrt{n} = 1.645 \times 300$

$\sqrt{n} = 1.645 \times 15$

$(\sqrt{n})^2 = (1.645 \times 15)^2$

n = 608.9

Rounding up, a sample of 609 nickels has to be weighed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

6 0

2 years ago

Which statement is true regarding the functions on the graph?

Kryger [21]

Answer:

this one is simple, you want to find what poits are on the line, so fibd what poits are on the line

8 0

3 years ago