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Oksanka [162]
3 years ago
11

Use Newton's second law of motion and a free-body diagram to...

Physics
1 answer:
timurjin [86]3 years ago
7 0
Using the formula F = m*a. where F is the force, m is the mass and a is the acceleration you can use it for each. As long as there are no other forces towards the body in both cases :
F = m*a
F = 50*3
F = 150 N
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A 297 g block is connected to a light spring with spring constant 4.34 N/m, and displaced 7.45 cm from equilibrium. It is then r
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Answer:

x = A sin ω t       describes the displacement of the particle

v = A ω cos ω t

a = -A ω^2 sin ω t        

a (max) = -A ω^2     is the max acceleration (- can be ignored here)

ω = (K/ m)^1/2        for SHM

F = - K x^2     restoring force of spring

K = 4.34 / .0745^2 = 782 N / m

ω = (782 / .297)^1/2 = 51.3 / sec

a (max) = .0745 * 782 / .297 = 196 m / s^2

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Answer:

Quick question do you mean what are some safety rules

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A Scooter travelling at 10m/s speed up to 20m/s in 4 sec.find the acceleration of scooter​
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Answer:

2.5 m/s²

Explanation:

Given,

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