Answer:how long it took you to get there and the distance between your house and her house
Explanation:
Answer:
Explanation:
A )
electric field E = V / d where V is potential difference between plates separated by distance d .
putting the given values
E = 370 / .040 V / m
= 9250 V / m
B )
Force on charged particle of charge q in electric field E
F = q E
F = 2.4 x 10⁻⁹ x 9250
= 22200 x 10⁻⁹
= 222 x 10⁻⁷ N .
C ) since field is uniform , force will be constant
work done by electric field putting up this force
= force x displacement
= 222 x 10⁻⁷ x 40 x 10⁻³
= 888 x 10⁻⁹ J
D )
change in potential energy
= q ( V₁ - V₂ )
= 2.40 X 10⁻⁹ x 370
= 888 x 10⁻⁹ J .
I had the same question. I'm pretty sure it's 23 seconds. :)
Answer:90 mins
Explanation:
majority of artificial satellites are placed in LEO, making one complete revolution around the Earth in about 90 minutes.
Answer:
a = 1.428 [m/s²]
v₀ = 5 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
x = final point [m]
x₀ = initial point [m]
v₀ = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
But we need to use this additional equation.
where:
vf = final velocity = 15 [m/s]
Now we can use this equation, replacing it, in the first one. We must bear in mind that the difference among x - x₀ is equal to 70 [m]
![x-x_{o}=v_{o}*t+\frac{1}{2}*a*t^{2} \\x-x_{o}=(v_{f}-a*t)*t+\frac{1}{2} *a*t^{2}\\70=(15-a*t)*t+\frac{1}{2}*a*t^{2}\\70=15*t-a*t^{2} +\frac{1}{2}*a*t^{2} \\70=15*t-\frac{1}{2}*a*t^{2}\\70=15*(7)-\frac{1}{2} *a*(7)^{2}\\105-70=0.5*a*49\\35=24.5*a\\a=1.428[m/s^{2} ]](https://tex.z-dn.net/?f=x-x_%7Bo%7D%3Dv_%7Bo%7D%2At%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%20%5C%5Cx-x_%7Bo%7D%3D%28v_%7Bf%7D-a%2At%29%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%2Aa%2At%5E%7B2%7D%5C%5C70%3D%2815-a%2At%29%2At%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%5C%5C70%3D15%2At-a%2At%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%20%5C%5C70%3D15%2At-%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E%7B2%7D%5C%5C70%3D15%2A%287%29-%5Cfrac%7B1%7D%7B2%7D%20%2Aa%2A%287%29%5E%7B2%7D%5C%5C105-70%3D0.5%2Aa%2A49%5C%5C35%3D24.5%2Aa%5C%5Ca%3D1.428%5Bm%2Fs%5E%7B2%7D%20%5D)
Now replacing this value in the second equation, we can find the initial velocity.
![15=v_{o}+1.428*7\\v_{o}=5[m/s]](https://tex.z-dn.net/?f=15%3Dv_%7Bo%7D%2B1.428%2A7%5C%5Cv_%7Bo%7D%3D5%5Bm%2Fs%5D)
