Answer:
1/6 or 1.6666666
Step-by-step explanation:
12 marbles, 2 yellow
12/2= 6
1/6
Answer:
c>16
Step-by-step explanation:
c-12>4
c> 4+12
c> 16
Using limits, the polynomial that has an even degree and a negative leading coefficient is:
Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.
<h3>What is a limit?</h3>
A limit is given by the value of function f(x) as x tends to a value.
In this problem, to find the polynomial, we have to find the limits as x goes to infinity, hence:
![\lim_{x \rightarrow -\infty} f(x) = [tex]\lim_{x \rightarrow -\infty} -a x^n](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Crightarrow%20-%5Cinfty%7D%20f%28x%29%20%3D%20%5Btex%5D%5Clim_%7Bx%20%5Crightarrow%20-%5Cinfty%7D%20-a%20x%5En)
Since n is even, we have that:
Since it goes down to the left and down to the right, hence the function is:
Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.
More can be learned about limits at brainly.com/question/26270080
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Answer:
The value of a=300 and value of k=200
If you solve the above system of equations by elimination method, you will get the same values of a and k.
In Equation 1
both variables k has 1 as their coefficient.
Step-by-step explanation:
We need to solve the system of equations using substitution method
The equation are:

For substitution method, we find value of k from equation 1 and put in equation 2

Putting it in eq(2)

So, we get value of a = 300
Now finding value of k by putting value of a in equation 

So, we get value of k =200
The value of a=300 and value of k=200
If you solve the above system of equations by elimination method, you will get the same values of a and k.
In Equation 1
both variables k has 1 as their coefficient.