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ZanzabumX [31]
3 years ago
13

Can the ratio 75 to 90 be simplified? If so, what is the simplified ratio?

Mathematics
1 answer:
Alina [70]3 years ago
6 0
75:90
15:18
5:6 is the simplified of 75:90
  
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A bag of marbpes contains 6 blue marbles, 2 yellow marbles, 4 red marbles, and 1 green marbpe. What is the probability of reachi
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1/6 or 1.6666666

Step-by-step explanation:

12 marbles, 2 yellow

12/2= 6

1/6

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Whats the inequality c−12>−4
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c>16

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c-12>4

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Which of the following polynomials has an even degree and a negative leading coefficient?
spin [16.1K]

Using limits, the polynomial that has an even degree and a negative leading coefficient is:

Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value.

In this problem, to find the polynomial, we have to find the limits as x goes to infinity, hence:

\lim_{x \rightarrow -\infty} f(x) = [tex]\lim_{x \rightarrow -\infty} -a x^n

Since n is even, we have that:

  • \lim_{x \rightarrow -\infty} -a (-\infty)^n = -a \times \infty = -\infty
  • \lim_{x \rightarrow \infty} -a (\infty)^n = -a \times \infty = -\infty

Since it goes down to the left and down to the right, hence the function is:

Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.

More can be learned about limits at brainly.com/question/26270080

#SPJ1

4 0
2 years ago
In in the previous activity you solved a system of equations representing the carnival admissions using the elimination method i
Mariulka [41]

Answer:

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 k+a=500 both variables k has 1 as their coefficient.

Step-by-step explanation:

We need to solve the system of equations using substitution method

The equation are:

k + a = 500--eq(1)\\3k + 10a = 3,600 --eq(2)

For substitution method, we find value of k from equation 1 and put in equation 2

From \ eq(1) \ we \ get\\k=500-a

Putting it in eq(2)

3k+10a=3600\\Put \ k=500-a\\3(500-a)+10a=3600\\1500-3a+10a=3600\\7a=3600-1500\\7a=2100\\a=\frac{2100}{7}\\a=300

So, we get value of a = 300

Now finding value of k by putting value of a in equation k=500-a

k=500-a\\Putting \ a \ =500\\k=500-300\\k=200

So, we get value of k =200

The value of a=300 and value of k=200

If you solve the above system of equations by elimination method, you will get the same values of a and k.

In Equation 1 k+a=500 both variables k has 1 as their coefficient.

4 0
2 years ago
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