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Nimfa-mama [501]
3 years ago
13

What is the value of x, rounded to the nearest degree? x ≈ ° According to the manufacturer, if the angle the ladder forms with t

he ground, x, is between 70° and 75°, then it meets safety standards. Is this ladder being used safely?.
Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

The measure of the value of x is 70.52 degrees.

Given

A 12-foot ladder is placed 4 feet away from a house as shown.

According to the manufacturer, if the angle the ladder forms with the ground, x, is between 70° and 75°, then it meets safety standards.

<h3>What is cos angle?</h3>

The cos theta is defined as the ratio of the side adjacent to the angle and the hypotenuse.

The following formula is used to calculate the value of x;

\rm Cosx=\dfrac{Side \ adjacent \ to \ angle}{Hypotenuse}\\

Where the side adjacent to angle = 4 and hypotenuse is 12.

Substitute all the values in the formula;

\rm Cosx=\dfrac{Side \ adjacent \ to \ angle}{Hypotenuse}\\\\\rm Cosx=\dfrac{4}{12}\\\\\rm Cosx=\dfrac{1}{3}\\\\x=Cos{-1}(\dfrac{1}{3}\\\\x= 70.52 \ degrees\\\\

Hence, the measure of the value of x is 70.52 degrees.

To know more about Trigonometric ratios click the link given below.

brainly.com/question/3630461

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Plz help me with this
Agata [3.3K]

Answer:

It's the first option.

Step-by-step explanation:

y = cos x transformed  to cos (x - π/2) moves  the graph  π/2 units to the right.

Multiplying by 3 to give 3 cos(x -  π/2)  stretches the graph 3 units parallel to the y-axis and adding 3 to this moves the graph up 3 units.

So the required equation is y = 3(cos x -  π/2) + 3.

3 0
3 years ago
At 1 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
Evgen [1.6K]
<span>The distance between the ships is changing at a rate of 21.393 km/h

</span><span>Step 1: First, you must draw an image to help better understand the problem 
</span>

The reason that ship A is moving -35km/h is because ship B acts as an "origin" and as things move closer to the "origin" they become negative and as things move away from the "origin" they become positive.

We know that the rate of Ship A is expressed as <span><span><span>dA</span><span>dt</span></span>=−35</span> and the rate of Ship B is expressed as <span><span><span>dB</span><span>dt</span></span>=25</span>

Step 2: We want to figure out how many km Ship A and Ship B traveled in 4 hours

<span>ShipA:−35<span><span>km</span>h</span>⋅4hr=−140km</span>

Now if we take this <span>−140km</span> and add it to the <span>150km</span> we can see that Ship A is now only <span>10km</span> away from where Ship B began

<span>ShipB:25<span><span>km</span>h</span>⋅4hr=100km</span>

This means that Ship B is now <span>100km</span> from where it originally started

We can now redraw our information

Step 3: We must use the Pythagorean Theorem to find the third side of the triangle

<span><span>x2</span>+<span>y2</span>=<span>z2</span>→<span>102</span>+<span>1002</span>=<span>z2</span></span>

<span>z=<span>√<span><span>102</span>+<span>1002</span></span></span></span>

Step 4: Now that we know z, we must differentiate the original equation in order to find the rate at which z in changing

<span><span>x2</span>+<span>y2</span>=<span>z2</span>→2x<span><span>dx</span><span>dt</span></span>+2y<span><span>dy</span><span>dt</span></span>=2z<span><span>dz</span><span>dt</span></span></span>

We can simplify by canceling out the 2's

<span>x<span><span>dx</span><span>dt</span></span>+y<span><span>dy</span><span>dt</span></span>=z<span><span>dz</span><span>dt</span></span></span>

Step 5: Write down all the information and then plug into equation

<span>x=10and<span><span>dx</span><span>dt</span></span>=−35</span>
<span>y=100and<span><span>dy</span><span>dt</span></span>=25</span>
<span>z=<span>√<span><span>102</span>+<span>1002</span></span></span>and<span><span>dz</span><span>dt</span></span>=?</span>

Now plug in the information

<span>x<span><span>dx</span><span>dt</span></span>+y<span><span>dy</span><span>dt</span></span>=z<span><span>dz</span><span>dt</span></span></span>

<span>10<span>(−35)</span>+100<span>(25)</span>=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>−350+2500=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>2150=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>21.393=<span><span>dz</span><span>dt</span></span></span>

The distance between the ships are increasing at a rate of 21.393 km/h

8 0
3 years ago
Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books
AlladinOne [14]

<u>Answers</u>

19 fiction books

7 nonfiction books


<u>Explanation</u>

x + y = 26  ............................................. (i)

x – y = 12  ............................................ (ii)

Elliot added the two equations and the result was

2x = 38.

Dividing both sides by 2;

x = 19

There are 19 fiction books.

Substituting x in equation (i),

x + y = 26             when x = 19

19 + y = 26

y = 26 - 19

   = 7

There are 7 nonfiction books

4 0
3 years ago
Read 2 more answers
Approximately how many square inches of space are blank?
ddd [48]

Answer:

blank area = 1.5π units²

Step-by-step explanation:

area of full circle = πr² = π6² = 36π units²

blank area = (15/360)(36π) = 1.5π units²

3 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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