Amber recorded the prices of candy, based on weight, from two different stores in the table and graph below.

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 w

irina1246 [14]

Answer:

A 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who eat cauliflower

n = sample of students

p = population proportion of students who eat cauliflower

Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

Now, in Agresti and Coull's method; the sample size and the sample proportion is calculated as;

$n = n + Z^{2}__(\frac{_\alpha}{2})$

n = $24 + 1.96^{2}$ = 27.842

$\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}$ = $\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}$ = 0.141

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ , $0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ ]

= [0.012, 0.270]

Therefore, a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95% confident that the proportion of students who eat cauliflower on Jane's campus is between 0.012 and 0.270.

7 0

3 years ago

Joey Chestnut is trying to break his own record for eating the most whole hot dogs in 101010 minutes. He needs to eat more than

anygoal [31]

Answer:

$9d+11\frac{1}{4}>72$

Step-by-step explanation:

We are supposed to write an inequality to determine the number of hot dogs per minute Joey must eat for the last 9 minutes to break his record.

Let d represent the number of hot dogs Joey eats per minute for the next 9 minutes.

We have been given that after 1 minute, Joey has eaten $11\frac{1}{4}$ hot dogs.

Hot dogs eaten in next 9 minutes would be 9 times d that is $9d$ .

Total hot dogs eaten by Joey would be hot dogs eaten in 1 minute plus next 9 minutes: $9d+11\frac{1}{4}$ .

Since to break the record Joey needs to eat more than 72 hot dogs. We can represent this information in an inequality as:

$9d+11\frac{1}{4}>72$

Therefore, our required inequality would be $9d+11\frac{1}{4}>72$ .

3 0

3 years ago

Reinhardt Furniture Company has 40,000 shares of cumulative preferred 2% stock, $150 par and 100,000 shares of $5 par common sto

Ann [662]

Answer:

for year 1

common stock = $1.75 per share

preferred stock = Zero

for year 2

common stock = $4.25 per share

preferred stock = $0.3 per share

for year 3

common stock = $3 per share

preferred stock = $2 per share

Step-by-step explanation:

step 1

preferred stock value = (40000 shares * $150) = $6000000

common stock value = (100000 shares * $5) = $500000

step 2

For year 1:

Dividend on preferred stock;

$\frac{6000000 * 2}{100}$ = $120000

But total dividend in the question was $70000 therefore total amount of dividend on cumulative preferred stock is $70000.

hence, dividend per share

$= \frac{70000}{40000 shares}$ = $1.75 per share

Dividend on common stock;

70,000 - 70,000 = Zero

as total dividend distributed in year 1 is insufficient for cumulative preferred stock therefore no dividend will be paid on common stock.

For year 2:

Dividend on cumulative preferred stock;

$\frac{6000000 * 2}{100}$ = $120000

extra dividend of year 1 ($120000 - $70000) = $50000

Thus total dividend on cumulative preferred stock

($120000 + $50000) = $170000

So dividend per share

$\frac{170000}{40000\ shares}$ = $4.25 per share

Dividend on common stock;

($200000 – $170000) = $30000

dividend per share

$\frac{30000}{100000\ shares}$ = $0.3 per share

For year 3:

Dividend on cumulative preferred stock;

$\frac{6000000 * 2}{100}$ = $120000

total dividend on cumulative preferred stock $120000

dividend per share

$\frac{120000}{40000 shares}$ = $3 per share

No dividend was extra in the year 2 therefore only available dividend of this year will be paid.

Dividend on common stock;

($320000 – $120000) = $200000

dividend per share

$\frac{200000}{100000\ shares}$ = $2 per share

3 0

3 years ago

Which subsets does 65/13 belong? Move the appropriate subsets into this box.

zhannawk [14.2K]

Answer:

roam

Step-by-step explanation:

free points

3 0

3 years ago

I need an answer asap

san4es73 [151]

Answer:

18

Step-by-step explanation:

note when dividing the denominator and numerators changes position so when it changes it will be 3×6=18

3 0

3 years ago

Read 2 more answers