All categories

2 years ago

Please answer and show the work! Will reward 100 points

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

8 0

$\\ \tt\longmapsto \dfrac{(-1)^7-2(3^2-2(4))}{3(\sqrt[3]{-216}+2^3)}$

$\\ \tt\longmapsto \dfrac{-1-2(1)}{3(6i+8)}$

$\\ \tt\longmapsto \dfrac{-1-2}{18i+24}$

$\\ \tt\longmapsto \dfrac{-3}{18i+24}$

$\\ \tt\longmapsto \dfrac{-1}{6i+8}$

ra1l [238]2 years ago

7 0

Answer:

- 1/6

Step-by-step explanation:

[(-1)⁷ - 2(3² - 2*4)] / [3(∛-216 + 2³)] =
[1 - 2(9 - 8)] / [3(-6 + 8)] =
(1 - 2*1) / (3*2) =
- 1/6

You might be interested in

Which description compares the vertical asymptotes of function A and function B correctly?

neonofarm [45]

Answer:

Option B:

Function A has a vertical asymptote at x = 1

Function B has a vertical asymptote at x = -3

Step-by-step explanation:

A function f(x) has a vertical asymptote if:

$\lim_{x \to\\k^+}f(x) = \±\infty\\\\ \lim_{x \to\\k^-}f(x) = \±\infty$

This means that if there is a value k for which f(x) has infinity or a -infinity then x = k is a vertical asymptote of f(x). Therefore, the closer x to k approaches, the closer the function becomes to infinity.

We can calculate the asymptote for function A.

$\lim_{x \to \\1^+}(\frac{1}{x-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{1^-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{0}) = \infty\\\\and\\ \lim_{x \to \\1^-}(\frac{1}{x-1})\\\\\lim_{x \to \\1^-}(\frac{1}{0}) = -\infty$

Then, function A has a vertical asymptote at x = 1.

The asymptote of function B can be easily observed in the graph. Note that the function b is not defined for x = -3 and when x is closest to -3, f(x) approaches infinity.

Therefore x = -3 is asintota of function B.

Therefore the correct answer is option B.

8 0

3 years ago

Find the value of x. Round to the nearest tenth. 35 12 х X ?

Anuta_ua [19.1K]

9514 1404 393

Answer:

6.9

Step-by-step explanation:

The relevant relation is ...

Sin = Opposite/Hypotenuse

Substituting given values, we have ...

sin(35°) = x/12

x = 12·sin(35°) ≈ 6.883

The value of x is about 6.9.

6 0

3 years ago

What is the slope of a line with endpoints (2,3) and (6,8)?

Yuki888 [10]

We don't need to graph the line. All we have to do is use our slope formula.

Answer is provided in the image attached.

4 0

3 years ago

Read 2 more answers

Can 171 19/32 be simplified

LenaWriter [7]

171 19/32=(171×32+19)/32=(odd number)/32.

But 32=2⁵

Thus, this ratio cannot be simplified, because the numerator is an odd number.

And the denominator is a power of 2.

7 0

4 years ago

(1.7 x 10^4) x (8.5 x 10 ^2)

vlabodo [156]

Answer:

144500

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers