Answer:
Step-by-step explanation:
How would I go about working out this type of question?
1 answer:
Answer:
j : k : m = 4 : 12 : 15
Step-by-step explanation:
Given
j : k = 1 : 3 , then k = 3j
Given
k : m = 4 : 5
then expressing in fractional terms
=
( substitute k = 3j )
=
( cross- multiply )
4m = 15j ( divide both sides by 4 )
m = j , so
j : k : m = 1 : 3 : ( multiply each part by 4 to clear the fraction )
= 4 : 12 : 15
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49. From 3 coin tosses, there are 8 possible outcomes:
... TTT, TTH, THT, THH, HTT, HTH, HHT, HHH
All but the first have at least one head, so 7/8 of the possibilities have at least one head. That's 87.5% (not among your choices).
Likewise, all but the last listed outcome have at least one tail. The problem is symmetrical that way when the coin is fair. 87.5% of outcomes have at least one tail.
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Perhaps you can tell I read your question as having two parts. If your question is the probability of getting at least one head AND at least one tail, you can see that condition includes 6 of the 8 outcomes, or 75%, matching selection d.
50. See for yourself: the calculator says 66.82%. Your best choice is selection d.
