I= PRT
7280=26000×0.07T
7280\1820=1820T\1820
4=T
dats all
The two numbers can be any factors of 120. This includes: (1,120) (2,60)(3,40)(4,30)(5,24)(6,20)(8,15)(10,12) and the reverse of this. The smallest perimeter would be the two numbers that are closer together, which is 10 and 12.
Answer:
c) parabola and circle: 0, 1, 2, 3, 4 times
d) parabola and hyperbola: 1, 2, 3 times
Step-by-step explanation:
c. A parabola can miss a circle, be tangent to it in 1 or 2 places, intersect it 2 places and be tangent at a 3rd, or intersect in 4 places.
__
d. A parabola must intersect a hyperbola in at least one place, but cannot intersect in more than 3 places. If the parabola is tangent to the hyperbola, the number of intersections will be 2.
If the parabola or the hyperbola are "off-axis", then the number of intersections may be 0 or 4 as well. Those cases seem to be excluded in this problem statement.
Answer:
u=-2
Step-by-step explanation:
Let's solve your equation step-by-step.
11u=−22
Step 1: Divide both sides by 11.
11u
11
=
−22
11
u=−2
Answer:
u=−2