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Alona [7]
3 years ago
5

In a race in which 10 automobiles are answered and there are no ties, in how many ways can the first three finishers come in ?

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0
Okay... so we have three places the automobiles can come in.

_ _ _

Now, how many automobiles have a chance of being in first place?

10.

Now, how many automobiles have a chance of being in second place now that the first place slot is taken?

9.

Now, how many automobiles have a chance of being in third place if the first and second place slots are taken by one automobile?

8.

Now multiply the numbers together to find the number of situations.

10 x 9 x 8 = 720.
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A recipe calls for 2 cups flour and 1 1/2 cup milk to make seven servings. Ming has plenty of​ flour, but only 5 cups of milk. H
Hoochie [10]

Answer:

21 or 23 servings.

Step-by-step explanation:

7 0
3 years ago
I need help with #6 please.
Juliette [100K]

9514 1404 393

Answer:

  6. (A, B, C) ≈ (112.4°, 29.5°, 38.0°)

  7. (a, b, C) ≈ (180.5, 238.5, 145°)

Step-by-step explanation:

My "work" is to make use of a triangle solver calculator. The results are attached. Triangle solvers are available for phone or tablet and on web sites. Many graphing calculators have triangle solvers built in.

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We suppose you're to make use of the Law of Sines and the Law of Cosines, as applicable.

6. When 3 sides are given, the Law of Cosines can be used to find the angles. For example, angle A can be found from ...

  A = arccos((b² +c² -a²)/(2bc))

  A = arccos((8² +10² -15²)/(2·8·10)) = arccos(-61/160) = 112.4°

The other angles can be found by permuting the variables appropriately.

  B = arccos((225 +100 -64)/(2·15·10) = arccos(261/300) ≈ 29.5°

The third angle can be found as the supplement to the other two.

  C = 180° -112.411° -29.541° = 38.048° ≈ 38.0°

The angles (A, B, C) are about (112.4°, 29.5°, 38.0°).

__

7. When insufficient information is given for the Law of Cosines, the Law of Sines can be useful. It tells us side lengths are proportional to the sine of the opposite angle. With two angles, we can find the third, and with any side length, we can then find the other side lengths.

  C = 180° -A -B = 145°

  a = c(sin(A)/sin(C)) = 400·sin(15°)/sin(145°) ≈ 180.49

  b = c(sin(B)/sin(C)) = 400·sin(20°)/sin(145°) ≈ 238.52

The measures (a, b, C) are about (180.5, 238.5, 145°).

7 0
3 years ago
What’s 12-1/3= as a fraction
aev [14]

12 - 1/3

= 36/3 - 1/3

= 35/3.

7 0
3 years ago
Read 2 more answers
KaVaugn wants to solve the following system using the elimination method:
UkoKoshka [18]
I believe that the answer is C
8 0
3 years ago
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Julia examines the two triangles below and determines that .
baherus [9]

IN Δ MLN:


∠M = 18.3 , ∠L = 98.6 AND ∠N = 180 - (∠M + ∠L) = 180 - (18.3 + 98.6 ) = 63.1



IN Δ FGH:


∠F = 98.6 , ∠G = 61.1 AND ∠H = 180 - (∠F + ∠G ) = 180 - (98.6 + 61.1 ) = 20.3



∴ ONLY ∠N = ∠F = 98.6


There is no other <span>congruent </span>angles


So, The correct statement is :

Inaccurate. The triangles are not similar because angle M is not congruent to angle H, and angle N is not congruent to angle G.



8 0
3 years ago
Read 2 more answers
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