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Alona [7]
3 years ago
5

In a race in which 10 automobiles are answered and there are no ties, in how many ways can the first three finishers come in ?

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0
Okay... so we have three places the automobiles can come in.

_ _ _

Now, how many automobiles have a chance of being in first place?

10.

Now, how many automobiles have a chance of being in second place now that the first place slot is taken?

9.

Now, how many automobiles have a chance of being in third place if the first and second place slots are taken by one automobile?

8.

Now multiply the numbers together to find the number of situations.

10 x 9 x 8 = 720.
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4 years ago
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Sta
nadezda [96]
Given: 
1. AB = 3x +2;  BC = 4x + 8;  AC = 38

2. AB + BC = AC                 incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38         correct
4. 7x + 10 = 38                    correct
5. 7x = 28                           correct
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Daniel made an error on line 2.
8 0
4 years ago
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Determine the quotient of 1 and 2 over 3 divided by 4 over 5 . (2 points)
saw5 [17]

Answer:

2 and 1 over 12

Step-by-step explanation:

1 \frac{2}{3}  \div  \frac{4}{5}  \\  \\  =  \frac{1 \times 3 + 2}{3}  \div  \frac{4}{5}  \\  \\  =  \frac{5}{3}  \times  \frac{5}{4}  \\  \\  =  \frac{25}{12}  \\  \\  = 2 \frac{1}{12}  \\

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3 years ago
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Answer:

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Step-by-step explanation:

15.63/3=5.21

One friend pays for the rest.

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salad=$2.45

5.21+3.87+2.45=11.53

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3 years ago
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