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bazaltina [42]
3 years ago
8

Two objects collide and stick together. Kinetic energy ​

Physics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

its inertia.

Inertia is the tendency of an object to continue in the state of rest or of uniform motion

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which of the four terms below includes the other three terms (1)community (2)ecosystem (3)population (4)individuala
Brut [27]
I think the answer is 3, population.
7 0
4 years ago
When a 58g tennis ball is served, it accelerates from rest to a constant speed of 36 m/s. The impact with the racket gives the b
inysia [295]
We first calculate the acceleration on the ball using:
2as = v² - u²; u = 0 because ball is initially at rest
a = (36)²/(2 x  0.35)
a = 1850 m/s²
F = ma
F = 0.058 x 1850
= 107.3 Newtons
5 0
3 years ago
A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
Pie

Answer:

0.128 s

Explanation:

We have to start by calculating the net force acting on the log. We have two forces:

- The constant pulling force, forward, of F = 2500 N

- The frictional force, backward

The frictional force is given by

F_f = \mu mg

where

\mu=0.45 is the coefficient of friction

m = 300 kg is the mass of the log

g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F_f = (0.45)(300)(9.8)=1323 N

So the net force acting on the log is

F=2500 - 1323=1177 N

Now, we can find the acceleration of the log by using Newton's second law

F=ma

where a is the acceleration. Re-arranging for a,

a=\frac{F}{m}=\frac{1177}{300}=3.92 m/s^2

And finally we can find the time it takes for the log to reach a speed of

v = 0.5 m/s

by using the suvat equation:

v=u+at

where u = 0 is the initial speed and t the time. Solving for t,

t=\frac{v}{a}=\frac{0.5}{3.92}=0.128 s

5 0
4 years ago
You drive 773 miles east, then turn around and drive 773 miles west. What is your displacement, to the nearest mile?
Oliga [24]

Answer:0miles

Explanation:

Since they are moving opposite direction we say

Displacement =773-773

Displacement =0miles

8 0
3 years ago
A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele
Lunna [17]

Answer:

Part a)

W = 0.15 J

Part b)

W = 0.11 J

Part c)

U = 0.19 J

Part d)

U = 0.038 J

Part e)

U = 0.075 J

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

W = mg(5R - R)

W = 0.032(9.8)(4)(0.12)

W = 0.15 J

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

W = mg(5R - 2R)

W = 3mgR

W = 0.11 J

Part c)

Potential energy at P point is given as

U = mgH

U = 0.032(9.8)(5)(0.12)

U = 0.19 J

Part d)

Potential energy at Q point is given as

U = mgH

U = 0.032(9.8)(0.12)

U = 0.038 J

Part e)

Potential energy at top point is given as

U = mgH

U = 0.032(9.8)(2)(0.12)

U = 0.075 J

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

8 0
4 years ago
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