Correct/Complete Question:
Under the _____, employers can be liable for current pay differences that are a result of discrimination that occurred many years earlier.
A. Sarbanes-Oxley Act
B. Lilly Ledbetter Fair Pay Act
C. Equal Pay Act
D. Fair Labor Standards Act
Answer:
B. Lilly Ledbetter Fair Pay Act
Explanation:
In 2009, the Lilly Ledbetter Fair Pay Act was enacted by the US congress. The act was aimed at worker protection against discrimination in pay thus giving individuals who are facing such situation a way to seek redress or rectification according to the federal anti discrimination law.
Cheers.
A)Money is the scarce resource because you only have enough for buying one thing.
B) movie or pizza
C)?
Answer:
$234.87
Explanation:
Pinky's new balance will be the opening balance plus additional. Deposits minus withdrawals. The new balance will be the starting balance plus cash-in minus the cash-out.
Starting balance =$137.66
Cash-in: $146.24
Cash-out : check $23.62 + (AT) of $25.41 =$49.03
New balance = $137.66 + $146.24 - $49.03
=$283.9- 49.03
=$234.8
Answer: 446
Explanation:
Net Income will be calculated as:
=(Sales - Operating costs - Depreciation - Bond × interest rate) × (1-tax rate)
= (8250 - 5750 - 1000) - (3200 × 5%) × (1-35%)
= 1500 - (3200 × 0.05) × 65%
= (1500 - 160) × 0.65
= 1340 × 0.65
= 871
Free Cash flow will be calculated as:
= (8250-5750-1000) × (1-35%) + 1000 - 1250 - 300
= 425
The firm's net income will exceed its free cash flow by:
= 871 - 425
= 446
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
