Answer:
4g/mol
Explanation:
Firstly, we can get the number of moles of the gas present using the ideal gas equation.
PV = nRT
Here:
P = 886 torr
V = 224ml = 224/1000 = 0.224L
T = 55 degrees celcius= 55+ 273.15 = 328.15K
R = molar gas constant = 62.36 L⋅Torr⋅K−1⋅mol−1
n = PV/RT
n = (886 * 0.224)/(62.36 * 328.15)
n = 0.009698469964 mole
Now to get the molar mass, this is mathematically equal to the mass divided by the number of moles. We have the mass and the number of moles, remaining only the molar mass.
First, we convert the mass to g and that is 38.8/1000 = 0.0388
The molar mass is thus 0.0388/0.009698469964 = 4g/mol
Donut flavor apple sauce with chicken strips
1. Answer:
1.0 × 10–9 M OH–
Explanation:
pH = -Log[H+]
pOH = -Log[OH-]
But;
pH + pOH = 14
Therefore;
[H+] + [OH-] = 1.0 × 10^-14 M
Therefore;
[OH-] = 1.0 × 10^-14 M - (1.0 × 10^–5 M)
= 1.0 × 10^-9 M OH–
2. Answer;
pH = 7.28
Explanation;
pH = -Log[H3O+]
Given;
[H3O+] = 5.2 × 10^–8 M
Therefore;
pH = - log [5.2 × 10^–8 M]
= 7.28
The pH is 7.28
Answer:
The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g
Explanation:
The given parameters are;
The volume of the copper sulfate solution = 100 cm³
The mass of the copper sulfate in the solution = 1.8 g
Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;
The mass of copper sulfate in 100 cm³ of the solution = 1.8 g
The mass of copper sulfate in 1 cm³ of the solution = 1.8 g/100 = 0.018 g
Therefore;
The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m = 25×0.018 g = 0.45 g
∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g
