Answer:
1.5 × 10⁻¹¹ M
Explanation:
Step 1: Given data
- Concentration of OH⁻ ([OH⁻]): 6.6 × 10⁻⁴ M
- Concentration of H⁺ ([H⁺]): ?
Step 2: Consider the self-ionization of water
H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)
Step 3: Calculate the molar concentration of H⁺
We will use the equilibrium constant for the self-ionization of water (Kw).
Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]
[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]
[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴
[H⁺] = 1.5 × 10⁻¹¹ M
The combines law of gas is:
P1 * V1 P2 * V2
---------- = -----------
T1 T2
So, you can obtain many equivalent valid forms depending on the variable that you solve for.
These are some examples:
Solve for T1:
T1 = T2 * (P1 * V1) / (P2 * V2)
Solve for V2:
V2 = V1 * (T2 / T1) * (P1 / P2)
Solve for P1:
P1 = P2 * (T1 / T2) * ( V2 / V1)
They push away from each other or repel due to the same charge they have.
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.
Answer is 1.42x10^24
