Water at the bottom of a narrow metal tube is held at a constant temperature of 293 K. The total pressure of air (assumed dry) i
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Given :
A 250 ml beaker weighs 13.473 g .
The same beaker plus 2.2 ml of water weighs 15.346 g.
To Find :
How much does the 2.2 ml of water, alone, weigh .
Solution :
Now, mass of water is given by :
Therefore , mass of 2.2 ml of water alone is 1.873 g .
Hence , this is the required solution .
Answer : The value of rate of reaction is
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The given chemical equation is:
Rate law expression for the reaction is:
As per question,
a = order with respect to = 2
b = order with respect to = 1
Thus, the rate law becomes:
Now, calculating the value of rate of reaction by using the rate law expression.
Given :
k = rate constant =
[NO] = concentration of NO =
= concentration of
=
Now put all the given values in the above expression, we get:
Hence, the value of rate of reaction is