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Genrish500 [490]
3 years ago
7

An inscribed angle and a central angle intercept the same arc. The inscribed angle is

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

Half

Step-by-step explanation:

An inscribed angle is an angle with its vertex on the circle and whose sides are chords. The intercepted arc is the arc that is inside the inscribed angle and whose endpoints are on the angle.

The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.

An image is inserted for your reference.

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On a trip that took 10 hours, Mark drove 2 fewer hours than Mary. How many hours did Mary drive?
alina1380 [7]

Answer:

7 hours

Step-by-step explanation:

Because ten minus two is seven

5 0
3 years ago
Read 2 more answers
A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of
Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

<u>Hours of TV per week (X)</u>: 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

                                P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of hours of TV watched per week = \frac{\sum X}{n} = 9.65

            s = sample standard deviation = \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }  = 4.61

            n = sample of people = 20

           \mu = true average number of hours of TV watched per week

<em>Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the true average, </u>\mu<u> is ;</u>

P(-1.33 < t_1_9 < 1.33) = 0.80  {As the critical value of t at 19 degrees of

                                               freedom are -1.33 & 1.33 with P = 10%}  

P(-1.33 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.33) = 0.80

P( -1.33 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.33 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.33 \times {\frac{s}{\sqrt{n} } } , \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 9.65-1.33 \times {\frac{4.61}{\sqrt{20} } } , 9.65+1.33 \times {\frac{4.61}{\sqrt{20} } } ]

                                         = [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0
3 years ago
Explain how combining like radicals is similar to combining like terms.
pickupchik [31]

Answer:

Just like combining like terms with the same variables, you combine like

radicals with the same number under the radical signs.

Step-by-step explanation:

Example:

3x + 2x

= 5x   {combined like terms}

3√2 + 2√2

= 5√2   {combined like radicals}

3 0
3 years ago
This equation has one solution.<br> 5(r–1) + 3r =7(r + 1)<br> What is the solution?
Marina CMI [18]

Answer:

5r-1+3r=7r+1

5r+3r-7r=1+1

r=2

If it helps you can I get brainliest

Step-by-step explanation:

5 0
3 years ago
these lines shown below are parallel. if the green line has a slope of -2, what is the slope of the red line?
Wittaler [7]

I think it should be +2


5 0
4 years ago
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