All categories

2 years ago

HELP ME WITH THIS . IF correct will get an brainliest HURRRY

Mathematics

2 answers:

tekilochka [14]2 years ago

7 0

X = 1

Explanation :

when you multiply negative 2 by negative six you get twelve. when you multiply positive one by negative six you get negative six.

Lunna [17]2 years ago

6 0

Answer: X = 1

Step-by-step explanation:

give other brainliest

You might be interested in

Answer please i will give brainliest

il63 [147K]

Step-by-step explanation:

simply add both equations

x + y = 2

-3x - y = 5

----------------

-2x + 0 = 7

x = -7/2

x + y = 2

-7/2 + y = 2

y = 2 + 7/2 = 4/2 + 7/2 = 11/2

1/2 x + 2y = -13

x - 4y = 8

first multiply the first equating by 2

x + 4y = -26

x - 4y = 8

--------------------

2x + 0 = -18

x = -18/2 = -9

x - 4y = 8

-9 - 4y = 8

-4y = 17

y = -17/4

7 0

3 years ago

Miss lawrence buys 8 ounces of smoked salmon at 17.98 per pound how much money does mis lawrence spend on smoked salmon

elena-14-01-66 [18.8K]

Do cross multiplication.
Convert ounce to pound.
8 ounce is 0.5 lbs
x/0.5 = 17.95/1
x=8.975
Miss Lawrence spent about $8.98

6 0

3 years ago

2. (01.07 MC)

Elena-2011 [213]

Part A: subtract 6 from both sides
Divide by -3 on both sides
X=-3
Part B: add like terms (-2K-3k)
Add 12 to both sides
Add 5k to both sides
Divide by 5 on both sides
K=3
Part C: distribute 6 into the parentheses
Add like terms together (36-5)
Subtract 1 from both sides
Subtract 36v from both sides
Divide by -30 on both sides
-1=v

7 0

3 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is <em>-10</em>.

3 0

3 years ago

use the elimination method to solve the system of equations. choose the correct ordered pair. 3x + 6y = 36 and 3x - 6y = 0

VladimirAG [237]

3x + 6y = 36

+ 3x - 6y =0

------------------------

6x = 36

x = 36/6

x = 6

3(6) - 6y = 0

18 - 6y = 0

-6y = -18

y = 3

7 0

3 years ago

Read 2 more answers