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zysi [14]
2 years ago
10

If I increase mass of 2 objects 2 times and increase the distance 2 times what happen to the force

Physics
1 answer:
vivado [14]2 years ago
5 0

Relation between Distance and acceleration

\\ \tt\longmapsto a=dv/dt

\\ \tt\longmapsto a=ds/dt^2

So

\\ \tt\longmapsto a\propto s

  • Acceleration is directly proportional to distance.

And

According to Newton's law

\\ \tt\longmapsto F=ma

\\ \tt\longmapsto F\propto m,a

  • So Force will be four times .
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A U-shaped tube open to the air at both ends contains water. A quantity of oil of unknown density is slowly poured into the righ
nadezda [96]

Answer:

\rho_o=600\ kg.m^{-3} is the density of the oil

Explanation:

Given:

  • height of oil column, h_o=20\ cm
  • oil column height that is more than the water column height in the other arm, \delta h=8\ cm

<u>Now from the given it is clear that the height of water column is:</u>

h_w=h_o-\delta h

h_w=20-8

h_w=12\ cm

Now according to the pressure balance condition of fluid columns:

Pressure due to water column = Pressure due to oil column

P_w=P_o

\rho_w.g.h_w=\rho_o.g.h_o

1000\times 9.8\times 0.12=\rho_o\times 9.8\times 0.2

\rho_o=600\ kg.m^{-3} is the density of the oil

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4 years ago
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Acids and bases create solutions in ________
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Balance. acids and bases counteract each other on the PH scale.
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4 years ago
A satellite orbits the earth a distance of 2.50 × 10^7 m above the planet’s surface and takes 6.43 hours for each revolution abo
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Answer:

2.30 m /sec2

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7 0
4 years ago
A balloon rises at the rate of 8 feet per second from a point on the ground 12 feet from an observer. To 2 decimal places in rad
Hitman42 [59]

Answer:

\displaystyle \theta' =0.24\ rad/s

Explanation:

<u>Rate Of Change</u>

Let some variable y depend on time t. we can express y as a function of t as

y=f(t)

The instant rate of change of y respect to t is the first derivative, i.e.

y'=f'(t)

The balloon, the ground and the observer form a right triangle (shown below) where the height of the balloon y, the horizontal distance x, and the angle of elevation are related with the trigonometric formula

\displaystyle tan\theta =\frac{y}{x}

Since x is constant, we take the derivative with respect to time  by using the chain rule:

\displaystyle sec^2\theta \ \theta' =\frac{y'}{x}

Solving for \theta'

\displaystyle \theta' =\frac{y'}{xsec^2\theta}

Let's compute the actual angle with the initial conditions y=9 feet, x=12 feet

\displaystyle tan\theta =\frac{y}{x}

\displaystyle tan\theta =\frac{9}{12}=\frac{3}{4}

Knowing that

\sec^2\theta=1+tan^2\theta

\displaystyle \sec^2\theta=1+\left(\frac{3}{4}\right)^2

\displaystyle \sec^2\theta=\frac{25}{16}

The balloon is rising at y'=8 feet/sec, thus we compute the change of the angle of elevation:

\displaystyle \theta' =\frac{8}{12\ \frac{25}{16}}

\displaystyle \theta' =\frac{32}{75}\ rad/s

\boxed{\displaystyle \theta' =0.43\ rad/s}

6 0
4 years ago
What is the average income of an osteologist? (Anatomy)
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