Answer:
The average induced emf in the coil is 0.0286 V
Explanation:
Given;
diameter of the wire, d = 11.2 cm = 0.112 m
initial magnetic field, B₁ = 0.53 T
final magnetic field, B₂ = 0.24 T
time of change in magnetic field, t = 0.1 s
The induced emf in the coil is calculated as;
E = A(dB)/dt
where;
A is area of the coil = πr²
r is the radius of the wire coil = 0.112m / 2 = 0.056 m
A = π(0.056)²
A = 0.00985 m²
E = -0.00985(B₂-B₁)/t
E = 0.00985(B₁-B₂)/t
E = 0.00985(0.53 - 0.24)/0.1
E = 0.00985 (0.29)/ 0.1
E = 0.0286 V
Therefore, the average induced emf in the coil is 0.0286 V
Answer:
Every action has an equal and opposite reaction. If the student doesn't push, nothing moves, is one student pushes, both move which is an example of newtons third law.
Explanation:
It has a high frenquency and can only travel through a medium
Answer:
1. 200 metres West
2. Dividing distance by time
3. Speed was unchanged
4. 1800 metres
5. 15 seconds
Explanation:
Running 500 metres West puts you 500 Metres west from the start. Then running 300 metres east puts you 200metres from where you started.
Since displacement is the distance you are from your original position 200 Metres West is the answer
2. Distance = Speed x Time
Rearrange that to get Speed = Distance / Time
3. Acceleration is when the rate of increase or decrease of speed or the direction is changing. When the speed or sirection dont change acceleration is 0
4. Distance = Speed x Time
60 x 30 = 1800 metres
5. Time = Distance / Speed
300 / 20 = 15 seconds
Answer: certificate authority
Explanation: The user submits Identification data and certificate request to the registration authority (RA). The RA validates this information and sends the certificate request to the certificate Authority (CA)
