Answer:
64
Step-by-step explanation:
1
2
3
4
1, 2
1, 3
1, 4
2, 1
2, 3
2, 4
3, 1
3, 2
3, 4
4, 1
4, 2
4, 3
1, 2, 3
1, 2, 4
1, 3, 2
1, 3, 4
1, 4, 2
1, 4, 3
2, 1, 3
2, 1, 4
2, 3, 1
2, 3, 4
2, 4, 1
2, 4, 3
3, 1, 2
3, 1, 4
3, 2, 1
3, 2, 4
3, 4, 1
3, 4, 2
4, 1, 2
4, 1, 3
4, 2, 1
4, 2, 3
4, 3, 1
4, 3, 2
1, 2, 3, 4
1, 2, 4, 3
1, 3, 2, 4
1, 3, 4, 2
1, 4, 2, 3
1, 4, 3, 2
2, 1, 3, 4
2, 1, 4, 3
2, 3, 1, 4
2, 3, 4, 1
2, 4, 1, 3
2, 4, 3, 1
3, 1, 2, 4
3, 1, 4, 2
3, 2, 1, 4
3, 2, 4, 1
3, 4, 1, 2
3, 4, 2, 1
4, 1, 2, 3
4, 1, 3, 2
4, 2, 1, 3
4, 2, 3, 1
4, 3, 1, 2
4, 3, 2, 1
Answer:
3
Step-by-step explanation:
(-7 - 5)/(0 - 4)
(-12)/(-4)
3
Answer:
18225
Step-by-step explanation:
Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
_____
The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.