1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dsp73
2 years ago
11

Please help me plsss!​

Physics
1 answer:
alexira [117]2 years ago
3 0

Answer:

A

Explanation:

You might be interested in
A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
rjkz [21]

Answer:

a) F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

b) \mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

Explanation:

In order to solve this problem we must first do a drawing of the situation and a free body diagram. (Check attached picture).

After a close look at the diagram and the problem we can see that the crate will have a constant velocity. This means there will be no acceleration to the crate so the sum of the forces must be equal to zero according to Newton's third law. So we can build a sum of forces in both x and y-direction. Let's start with the analysis of the forces in the y-direction:

\Sigma F_{y}=0

We can see there are three forces acting in the y-direction, the weight of the crate, the normal force and the force in the y-direction, so our sum of forces is:

-F_{y}-W+N=0

When solving for the normal force we get:

N=F_{y}+W

we know that

W=mg

and

F_{y}=Fsin \theta

so after substituting we get that

N=F sin θ +mg

We also know that the kinetic friction is defined to be:

f_{k}=\mu_{k}N

so we can find the kinetic friction by substituting for N, so we get:

f_{k}=\mu_{k}(F sin \theta +mg)

Now we can find the sum of forces in x:

\Sigma F_{x}=0

so after analyzing the diagram we can build our sum of forces to be:

-f+F_{x}=0

we know that:

F_{x}=Fcos \theta

so we can substitute the equations we already have in the sum of forces on x so we get:

-\mu_{k}(F sin \theta +mg)+Fcos \theta=0

so now we can solve for the force, we start by distributing \mu_{k} so we get:

-\mu_{k}F sin \theta -\mu_{k}mg)+Fcos \theta=0

we add \mu_{k}mg to both sides so we get:

-\mu_{k}F sin \theta +Fcos \theta=\mu_{k}mg

Nos we factor F so we get:

F(cos \theta-\mu_{k} sin \theta)=\mu_{k}mg

and now we divide both sides of the equation into (cos \theta-\mu_{k} sin \theta) so we get:

F=\frac{\mu_{k}mg}{cos \theta-\mu_{k}sin \theta}

which is our answer to part a.

Now, for part b, we will have the exact same free body diagram, with the difference that the friction coefficient we will use for this part will be the static friction coefficient, so by following the same procedure we followed on the previous problem we get the equations:

f_{s}=\mu_{s}(F sin \theta +mg)

and

F cos θ = f

when substituting one into the other we get:

F cos \theta=\mu_{s}(F sin \theta +mg)

which can be solved for the static friction coefficient so we get:

\mu_{s}=\frac{Fcos \theta}{Fsin \theta +mg}

which is the answer to part b.

3 0
3 years ago
Read 2 more answers
A Truck with a mass of 1500 kg is decelerated At a rate of 5m/s2. how much force did this require
Marianna [84]
(1500 kg)*(5 m/s^2) = 7500 N
6 0
3 years ago
What is light? Makes thing visible?
Alecsey [184]

Yes, light enters your eye and makes things visible. It's only a small portion of the elctromagnetic spectrum. It's called "visible light." What other things does the question want to know? I could go in a describe what light really is but I think itd be unnecessary.

6 0
3 years ago
A block starting from rest slides down the length of an 18 plank with an acceleration of 4.0 meters per second. How long does th
Snowcat [4.5K]

Answer:

\boxed{\text{\sf \Large 3.0 s}}

Explanation:

Use distance formula

\displaystyle d=ut+\frac{1}{2} at^2

u= \text{\sf  initial velocity}\\d= \text{\sf  distance}\\a= \text{\sf  acceleration}\\t= \text{\sf  time taken}

\displaystyle 18=0 \times t+\frac{1}{2} \times 4 \times t^2

t=3

4 0
3 years ago
A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. However, he is unable to lift the suit
kvasek [131]

Answer:

b)

Explanation:

Normal force, is always directed upward the surface over which is placed the object, and can adopt any value, as required to meet Newton's 2nd Law.

In this case, as the external force on the suitcase pulls upward, in order  to counteract the influence of gravity, normal force is less than the weight of the suitcase, as follows:

F + Fn = m*g

⇒ Fn = m*g - F

So, the normal force is equal to the magnitude of the weight of the suitcase (m*g) minus the magnitude of the force of the pull (F) which is the same expressed by the statement b.

4 0
3 years ago
Other questions:
  • Two laws are described below:
    12·1 answer
  • Unpolarized light passes through two polarizers. Find the fraction of light from the first polarizer that gets through the secon
    15·2 answers
  • What is a population?
    13·1 answer
  • Nate the Skate was an avid physics student whose main non-physics interest in life was high-speed skateboarding. In particular,
    15·1 answer
  • (a) What is the sum of the following four vectors in unit-vector notation? For that sum, what are (b) the magnitude, (c) the ang
    14·1 answer
  • How many Joules of energy are required to run a 100W light bulb for one day?
    15·1 answer
  • If the frequency of a wave is 25Hz, what is the period of 1 wave?
    10·2 answers
  • A bag contains lenses with focal lengths 10 cm, 20 cm and 25 cm which are not marked with their focal length. Describe a simple
    10·1 answer
  • What is the meaning of inversely proportion​
    13·2 answers
  • Rearrange the equation = KE<br> -1<br> 2<br> - my? to solve for v. Show your work.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!