Answer:
The horizontal distance covered by the firework will be 
Explanation:
Let acceleration due to gravity on the planet be g, initial velocity of the firework be u and angle made with the horizontal be ∅.
writing equation of motion in vertical direction:


and 
therefore 
writing equation of motion in horizontal direction:


therefore the equation becomes 
therefore horizontal distance traveled =
The convection going on with the magma in the asthenosphere
Answer:
20 °C
Explanation:
Ideal gas law:
PV = nRT
Rearranging:
P / T = nR / V
Since n, R, and V are constant:
P₁ / T₁ = P₂ / T₂
488.2 kPa / T = 468 kPa / 281.15 K
T = 293.29 K
T = 20.1 °C
Rounded, the temperature was 20 °C.
Hubble space telescope, Hubble deep field guide, moon, mercury, Saturn, sun, galaxy messier 101