Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.
Answer:
he affirmations the correct ones are: A and D
Explanation:
To find out which expressions are correct, let's calculate the work and power done by each person
the expression for work is W = F and
the expression for power is P = W / t
In this case the work is positive because the beast is in the same direction of displacement.
Ted
W₁ = 10 1.5
W₁ = 15 J
P₁ = 15/1
P₁ = 15 w
Johnny
the job
W₂ = 10 1.5
W₂ = 15 J
the potential
P₂ = 15/2
P₂ = 7.5 w
therefore we see that the work of both is the same, but Ted developed twice as much power as Johnny
when resisting the affirmations the correct ones are: A and D
Answer:
d in my opinion is the most opitmal answer
Explanation:
aka a graph comparing distances traveled by objects thrown on Earth and the moon
Answer:
The rate clock is about
F = 8 GHz
Explanation:
f₁ = 4 G Hz , t₁ = 10 s , t₂ = 6s , f₂ = 1.2 f₁
Can organize to find the rate clock the designer build to the target so
X / 4 Ghz = 10 s , 1.2 X / Y = 6 s
X * Y = 10 s ⇒ F = 10 s
1.2 * 4 G Hz = 6 s
F = 10 * ( 1.2 * 4 G Hz ) / 6
F = 10 * ( 1.2 * 4 x 10 ⁹ Hz ) / 6
F = 8 x 10 ⁹ Hz
F = 8 GHz
∑ <em>F</em> (horizontal) = (150 N) cos(60°) - 15 N = (20 kg) <em>a</em>
==> <em>a</em> = ((150 N) cos(60°) - 15 N)/(20 kg) = 3 m/s²
