Answer:
Explanation:
a ) Let the distance required in former case be d₁ .
initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 7.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 7 x d₁
d₁ = 64.28 m
b) initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 5.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 5 x d₂
d₂ = 90 m
c)
t = .5 s
s₁ = ut - .5 at²
= 30 x .5 - .5 x 7 x .5²
= 15 - .875
= 14.125 m
t = .5 s
s₂ = ut - .5 at²
= 30 x .5 - .5 x 5 x .5²
= 15 - .625
= 14.375 m
Explanation:
It is given that, the field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs
Change in magnetic field, 
Change in time, 
Diameter, d = 2.3 cm
Radius, r = 0.0115 m
Emf is induced in the ring as the field changes. It is given by :
E = 5.19 volts
So, the emf induced in the ring is 5.19 volts. Hence, this is the required solution.
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
Answer:
C. tiny particles called charges flowing through the wires.
Explanation:
<h3> Hello!</h3>
An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
Hope it helps!
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