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ahrayia [7]
2 years ago
8

Ntate runs 12 km in 3 hours. how many hours will it take him to run in 1 km​

Mathematics
1 answer:
docker41 [41]2 years ago
5 0

Answer:

15 minutes or 1/4 hour

Step-by-step explanation:

3 hours = 60*3=180

180/12=15

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Write a function to model the data.?
Wewaii [24]

Answer:

the seven question is not clear

6 0
3 years ago
Slope of (3, 300)(5, 180) in y=mx+b form​
vredina [299]

Answer: ok so if you look at the difference it is 120 in 2 hours so to find 1 hour you divide it by 2, or split it in half and that means 60 and it is Decreasing so c is the answer. As for what y= it is y=-60x+480

60 cubic feet and you start out with 480

Step-by-step explanation:

120/2=60

decreasing

c

And y=-60x+480

6 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
I need help with this math
enot [183]

Answer:

question? haven't learn this yet but try asking desmos that app helps me a lot!

3 0
3 years ago
The diameter of a circle is 1.4 centimeters. Find its area. Use 3.14 Round to the nearest
NeTakaya

Answer:

Area = 1.54

Step-by-step explanation:

Area = πr^{2}

π = 3.14

diameter = 1.4

radius (half of diameter) = 0.7

Area = 3.14 x 0.7^{2}

Area = 3.14 x 0.49

Area = 1.5386

round to the nearest hundredth:

1.5386 = 1.54

8 0
2 years ago
Read 2 more answers
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