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yKpoI14uk [10]
3 years ago
14

Which expression is equivalent to(r^-7)^6?

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0

Answer:

\frac{1}{r^{42}} is equivalent to (r^{-7})^6

Step-by-step explanation:

Using the exponent rule:

(a^n)^m = a^{nm}

a^{-n} = \frac{1}{a^n}

Given the radical expression:

(r^{-7})^6

Apply the rule we have;

r^{-7 \cdot 6}

Simplify:

r^{-42}

Again, apply the rule:

\frac{1}{r^{42}}

Therefore, the expression is equivalent to (r^{-7})^6

\frac{1}{r^{42}}.

shtirl [24]3 years ago
4 0
(r^-7)^6 = r^-42 . . . . exponents are multiplied
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Lets do the same for f(x)

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By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

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4

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When need to find x axis y is =0

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3 years ago
The sum of two numbers is 108. the difference of the same numbers is 78. what are the numbers
Nimfa-mama [501]

The sum of two numbers:

x + y = 108

The difference of the same two numbers:

x - y = 78

We can use substitution to figure out x and y:

x - y = 78 can be changed to x = 78 + y

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78 + y + y = 108

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The radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had los
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The bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

<h3>What is half-lives?</h3>

Half lives is the time interval which is need to decay the atomic nuclei of a radioactive sample.

There is a scientist who determined that the bones from a mastodon had lost 70.3​% of their​ carbon-14.  Thus, the fraction remaining is,

f=1-(70.3/100)=1-0.703

f=1-(70.3/100)=0.297

Now the fraction remaining can be given as,

f=(1/2)ⁿ

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The radioactive element​ carbon-14 has a​ half-life of total 5750 years. Thus,

Years=1.75*5750

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Thus, the bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

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