Answer:
1. λ = 5.60 m
, 2. T = 5.80 s 3. v = 0.966 m/s 4. A = 0.315 m
Explanation:
1. The definition of wavelength is the distance between two consecutive maximums or minimums, so that the wave is repeated, in this case they give us the distance between two consecutive maximums, therefore
λ = 5.60 m
2. the period is the time it takes for the wave to start repeating itself, going through the same point. They give time to go from the highest point to the lowest point, which is the time for half a wavelength, so the time for a wavelength is
T = 2 t
T = 2 2.90
T = 5.80 s
3. For all waves the speed is the product of the wavelength by the frequency and the frequency is the inverse of the period
v = λ f
f = 1 / T
v = λ / T
v = 5.60 / 5.80
v = 0.966 m / s
4. The amplitude of the wave is the value of the zero displacement point to the maximum displacement point, give the value between the maximum and minimum displacement
A = d / 2
A = 0.63 / 2
A = 0.315 m
Answer:
θ = 12.95º
Explanation:
For this exercise it is best to separate the process into two parts, one where they collide and another where the system moves altar the maximum height
Let's start by finding the speed of the bar plus clay ball system, using amount of momentum
The mass of the bar (M = 0.080 kg) and the mass of the clay ball (m = 0.015 kg) with speed (v₀ = 2.0 m / s)
Initial before the crash
p₀ = m v₀
Final after the crash before starting the movement
= (m + M) v
p₀ =
m v₀ = (m + M) v
v = v₀ m / (m + M)
v = 2.0 0.015 / (0.015 +0.080)
v = 0.316 m / s
With this speed the clay plus bar system comes out, let's use the concept of conservation of mechanical energy
Lower
Em₀ = K = ½ (m + M) v²
Higher
= U = (m + M) g y
Em₀ =
½ (m + M) v² = (m + M) g y
y = ½ v² / g
y = ½ 0.316² / 9.8
y = 0.00509 m
Let's look for the angle the height from the pivot point is
L = 0.40 / 2 = 0.20 cm
The distance that went up is
y = L - L cos θ
cos θ = (L-y) / L
θ = cos⁻¹ (L-y) / L
θ = cos⁻¹-1 ((0.20 - 0.00509) /0.20)
θ = 12.95º
How many atoms are in something determines it "mass"
<span>Potential energy and Kinetic energy</span>
I’m pretty sure it’s true x