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Airida [17]
3 years ago
11

In each case, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The

ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask. Which image represents a gaining of a charge on the leaves of the electroscope by conduction In each case, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask. Which image represents a gaining of a charge on the leaves of the electroscope by conduction? A) A B) B C) C D) D
Physics
2 answers:
Art [367]3 years ago
8 0

Answer:

b

Explanation

B represents a charge gained by induction. In this case, the rod is not touching the electroscope and the leaves are charged similarly because they are repelling each other. The charge is gained (induced) by the nearness of the oppositely charged rod.

on:

Evgen [1.6K]3 years ago
5 0

Answer:

D

Explanation:

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pentagon [3]

Answer:

Explanation:

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3 years ago
n oscillator is driven by a sinusoidal force. The frequency of the applied force A : must be less than the natural frequency of
lilavasa [31]

Answer:

  B : is independent of the natural frequency of the oscillator

Explanation:

You can apply any force you like to a natural oscillator. It is independent of the natural frequency of the oscillator.

The result you get will depend on how the frequency of the applied force and the natural frequency relate to each other. It will also depend on the robustness of the oscillator with respect to the applied force.

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3 years ago
two objects are in uniform circular motion at the same speed but at different radii. the ones with the __ radius has the largest
Cerrena [4.2K]

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5 0
3 years ago
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What is the gravitational field theory and how does it work? four mark answer. Don't give me random answers just for points or i
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2 years ago
As seen in the figure, a bullet with mass of 15.0-g is fired vertically and penetrates a block with mass of 2.5-kg and the block
rodikova [14]

Answer:

KE = 2.03 J

Explanation:

After impact, the kinetic energy of the bullet+block will convert to potential energy

½mv² = mgh

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0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)

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KE = 2.03 J

4 0
3 years ago
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