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Airida [17]
3 years ago
11

In each case, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The

ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask. Which image represents a gaining of a charge on the leaves of the electroscope by conduction In each case, a charged rod, made of the dense rubber ebonite, comes close or is in contact with the top of an electroscope. The ball on top of the electroscope is directly connected to the two metal leaves suspended in the flask. Which image represents a gaining of a charge on the leaves of the electroscope by conduction? A) A B) B C) C D) D
Physics
2 answers:
Art [367]3 years ago
8 0

Answer:

b

Explanation

B represents a charge gained by induction. In this case, the rod is not touching the electroscope and the leaves are charged similarly because they are repelling each other. The charge is gained (induced) by the nearness of the oppositely charged rod.

on:

Evgen [1.6K]3 years ago
5 0

Answer:

D

Explanation:

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The mass of the Sun is 1. 99 × 1030 kg. Jupiter is 7. 79 × 108 km away from the Sun and has a mass of 1. 90 × 1027 kg. The gravi
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The gravitational force is s type of force that has the ability to attract any two objects having mass. The gravitational force will be 4.16\times10^{23}.

<h3>What is the gravitational force?</h3>

The gravitational force is s type of force that has the ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other.

                      F= G\frac{m_1m_2}{r^{2} }

Given,

mass of the sun (m_1)= 1.99\times10^{23} kg

mass of Jupiter(m_2)= 7.79\times10^{8} kg

distance between the sun and Jupiter (r)= 1.90\times10^{27} m

F= G\frac{m_1m_2}{r^{2} }\\\\\\F=4.16\times10^{23}\times\frac{1.99\times10^{23}\times7.79\times10^{8}}{({1.90\times10^{27})^2} }

F= 4.16\times(10)^{23}   Newton

Hence the gravitational force between the sun and Jupiter will be 4.16\times10^{23}

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2 years ago
Two electrons with a charge of magnitude 1.6×10-19 C in an atom are separated by 1.5×10-10 m, the typical size of an atom. What
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Answer:

1.02\cdot 10^{-8} N, repulsive

Explanation:

The magnitude of the electric force between two charged particles is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges of the two particles

r is the separation between the two charges

The force is:

- repulsive if the two charges have  same  sign

- Attractive if the two charges have opposite signs

In this problem, we have two electrons, so:

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the two electrons

r=1.5\cdot 10^{-10} m is their separation

Substituting into the formula, we find the electric force between them:

F=(8.99\cdot 10^9)\frac{(1.6\cdot 10^{-19})^2}{(1.5\cdot 10^{-10})^2}=1.02\cdot 10^{-8} N

And the force is repulsive, since the two electrons have same sign charge.

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2 years ago
Is there a change in speed from when a tennis ball first starts bouncing to when it is near the end of the bounce? How can you t
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The potential energy is stronger at the start of the bounce and when it is near the end bounce the balls accelerated rate will be lower because the force has decreased . Also I love your profile picture miraculous rocks !

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2 years ago
Unpolarized light with intensity 300 W/m^2 passes first through a polarizing filter with its axis vertical, then through a secon
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Answer:

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

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