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2 years ago

DCB is a right angel +35 degrees =90 degrees X degrees =

Mathematics

1 answer:

Vikentia [17]2 years ago

5 0

Answer:

55 degrees

Step-by-step explanation:

It is given that DCB is a right angle. So the angles are complementary angles

It means that, x+35 degrees = 90

that is, x=90-35= 55 degrees

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What is (12-2i) (5+3i) multiplied?

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3 years ago

Find x and y, given that line WS and line VT are parallel. Show all work!

bulgar [2K]

In the given diagram, the traingles USW and UTV are similar triangles and thus the following ratio equality applies to them.

$\frac{VT}{WS} =\frac{VU}{WU}=\frac{TU}{SU}$ ..........(Equation 1)

Checking the diagram given, we see that:

VT=y, WS=22, VU=8, ST=x-2

WU=WV+VU=12+8=20

TU=5

SU=ST+TU=(x-2)+5=x+3

Thus, substituting the required values in (Equation 1) we get:

$\frac{y}{22}=\frac{8}{20}=\frac{5}{x+3}$

Now, as can be clearly seen, to find y we will use the first two ratios as:

$\frac{y}{22}=\frac{8}{20}$

$y=\frac{8\times 22}{20}=8.8$

In a similar manner, to find the value of x we can use the last two ratios:

$\frac{8}{20}=\frac{5}{x+3}$

After cross multiplication we get:

$5\times 20=8(x+3)$

Which can be simplified as:

$x+3=\frac{100}{8} =12.5$

Thus, $x=12.5-3=9.5$

Therefore, the required answer is:

x=9.5 and y=8.8

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3 years ago

Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of

Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

$\mathbf{L = (0,0)}$

$\mathbf{M = (3,0)}$

$\mathbf{N = (3,7)}$

$\mathbf{O = (0,7)}$

P is the midpoint of LM.

So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

$\mathbf{PQ = \sqrt{ 7^2}}$

$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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2 years ago

DCB is a right angel ____ +35 degrees =90 degrees X degrees =____

DCB is a right angel +35 degrees =90 degrees X degrees =