Complete Question
A random sample of 300 circuits generated 13 defectives. a. Use the data to test

Versus

Use α = 0.05. Find the P-value for the test
Answer:
The p-value is
Step-by-step explanation:
From the question we are told that
The sample size is n = 300
The number of defective circuits is k = 13
Generally the sample proportion of defective circuits is mathematically represented as

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Generally the standard Error is mathematically represented as

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Generally the test statistics is mathematically represented as

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From the z table the area under the normal curve to the left corresponding to -0.5317 is

Generally the p-value is mathematically represented as

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I'll do problem 1 to get you started.
The vertical sides are 3 and x for the left and right figures.
The horizontal sides are 15 and 60 for the left and right figures.
The corresponding sides form fractions which are equal (due to the nature of the similar polygons)
3/x = 15/60
3*60 = x*15 ... cross multiply
180 = 15x
15x = 180
x = 180/15 .... divide both sides by 15
x = 12
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Another way you can see this is note how the jump from 15 to 60 is "times 4", so the jump from 3 to x must also be "times 4" to keep the same proportion
3 ---> x = 3*4 = 12
Or you could set up the proportion
60/15 = x/3
4 = x/3
x/3 = 4
x = 3*4
x = 12
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<h3>Final Answer: 12</h3>
Answer:
18
Step-by-step explanation:
3/5 x 30
(3 times 30)divided by 5
= 18 children are going.
Hope this helps:-)
Answer:
x =√[y²+(27)²] = √[ z² - 3² +(27)²]
Step-by-step explanation:
step 1) x=√[y²+(27)²]
step 2)
We find y
z²=y²+3² → y² = z² - 3²
step 3) x = √[ z² - 3² +(27)²]