The system of equations of two unknowns is formulated and solved.
The fraction that satisfies the request is 
, since in 
the negative signs are canceled and the first fraction is obtained.
It can go into 136 4 times. Just do 136 divided by 34. It's even enough to go into it.
Answer:
You will need 20 sides to complete the loop.
Step-by-step explanation:
The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop
We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV
With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.
108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.
This means that each polygon is rotated 18 degrees relative to it's neighbour.
With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.
First, we must express the ratio of rent to Joel's total earning. 375 out of 1500 in its simplest form is 1/4. To express a value in percentage, we must multiply it to 100. Thus, for this case, we have
1/4 x 100 = 25%
That means, out of a total of 100%, Joel spends 25%<span>of his income on rent.</span>
2500(.054)(2) = 270
270+2500=2770
The total amount he would pay is $2770
Happy to help,
~BP98
