Based on the CPCTC theorem, the congruences that are true about the given triangles are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
<h3>What is the CPCTC Theorem?</h3>
According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.
Given that triangles JKL and RST are congruent to each other, therefore:
∠J ≅ ∠R
∠K ≅ ∠S
∠L ≅ ∠T
JK ≅ RS
KL ≅ ST
JL ≅ RT
Therefore, the congruences that would be true by CPCTC are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
Learn more about the CPCTC theorem on:
brainly.com/question/14706064
#SPJ1
3(x-2)=36
3x-6=36
3x=36+6
3x=42
x=42/3
x=14
Answer: 14
I hope this helped mate!
The toal surface area of a cylinder is 2πrh+2πr²
Step-by-step explanation:
The "net" of any geometrical shape refers to the two-dimensional equivalents of the three-dimensional object.
e.g. geometrical net of a cylinder would consist of two circles (one each at top and bottom) and a rectangle extending from bottom to the top in a curvilinear manner.
Hence, the Total surface area (TSA) of the cylinder can be found
by considering cylinder to be made of three parts
- the circle at the bottom
- the circular tube which extends for height "h" of the cylinder
- the circle at the top (considering it is closed cylinder)
The surface area of a circle (for 2-dimensional figures surface area is the same as area since the thickness factor is 1)= πr²
Since there are two circles= surface area (combined)= 2πr²
Moreover, this circle extends to height h. Hence, the combined surface area of the circle extending to height h (int he forms of the tube)= circumference*height= 2πrh
hence TSA= 2πrh+ 2πr²