Answer:
Explanation:
Object distance = distance between object and lens
u = 50 - 12 = 38 cm
image distance v = 88 - 50 = 38 cm
i )
using lens formula
1 / v - 1 / u = 1 / f
1 / 38 - 1 / - 38 = 1/f
2 / 38 = 1 / f
f = 19 cm
ii ) So object is placed at 2 f or at the center of curvature of the lens .
If object distance is changed to 50 - 31 = 19 cm
using lens formula
1 / v - 1 / u = 1 / f
1 / v + 1 / 19 = 1/19
1 / v = 0
v = infinity
It is so because now the object is placed at the focal distance
iii )
If object further shifts towards the lens , then virtual image of object will be formed behind the lens which will be larger than object .
False. The sun from earth looks yellow, orange, or sometimes red, but it is really a big white ball of fire.
The temperature of the water and the and the salinity of water
Answer:
T = 27.92 N
Explanation:
For this exercise let's use Newton's second law
T - W = m a
The weight
W = mg
The acceleration can be found by derivatives
a = dv / dt
v = 2 t + 0.6 t²
a = 2 + 0.6 t
We replace
T - mg = m (2 + 0.6t)
T = m (g + 2 + 0.6 t) (1)
Let's look for the time for the speed of 15 m / s
15 = 2 t + 0.6 t²
0.6 t² + 2 t - 15 = 0
We solve the second degree equation
t = [-2 ±√(4 - 4 0.6 (-15))] / 2 0.6
t = [-2 ±√40] / 1.3 = [-2 ± 6.325] / 1.2
We take the positive time
t = 3.6 s
Let's calculate from equation 1
T = 2.00 (9.8 + 2 + 0. 6 3.6)
T = 27.92 N