Answer:
Get to work.
Explanation:
This is not Brainly material. This is a project that you need to get started on and do your best on. It always looks worst before you get started on it. Just sink your teeth in and you'll be finishing it up before you know it.
Answer:
V = 0.896 m/s
Explanation:
This is a typical problem of momentum conservation, whic states the following:
m₁V₁ + m₂V₂ = m₁V₃ + m₂V₄ (1)
In this case V₃ and V₄ would be the final velocity of the trucks after the collision.
With the given data let's see what we have:
m₁ = 5.5x10⁵ kg
m₂ = 2.3x10⁵ kg
V₁ = 5 m/s
V₂ = -5 m/s because it's going to the left (-x axis)
V₄ = 9.1 m/s to the right (Meaning is positive)
V₃ = ??
So to calculate V₃ we just need to replace the data into (1) and solve for V₃:
(5.5x10⁵ * 5) - (2.3x10⁵ * 5) = 5.5x10⁵V₃ + (2.3x10⁵ * 9.1)
2.75x10⁶ + 1.15x10⁶ = 5.5x10⁵V₃ + 2.093x10⁶
V₃ = 2.75x10⁶ - 1.15x10⁶ - 2.093x10⁶ / 5.5x10⁵
V₃ = -0.493x10⁶ / 5.5x10⁵
V₃ = -0.896 m/s
With this sign, it means that is going in the same sense of the other truck, but it's going to the left so this would be positive:
<h2>
V₃ = 0.896 m/s</h2>
Hope this helps
Answer:
A. Force on parent is greater than the force on child
B. The net force acting on the bodies is zero for each.
C. the drag force on the parent is greater than the drag force on the child.
Explanation:
The child and the parent jump together form a certain height where the mass of the parent is greater than the mass of the child.
A
Before opening the parachute the drag force is negligible and so their velocity and acceleration are same simultaneously. The total force acting on the child is lesser than the total force of gravity on the child because the force of gravity is given as:
where:
m= mass
g= acceleration due to gravity
So when the mass is greater then the force of gravity is also greater on the body.
B
During the uniform velocity motion there is no acceleration in the body and hence we can say the there is no net force acting on the body.
The net force acting on the body is zero.
C
The force of drag acts due to parachute on each of the body when falling with uniform motion, this drag force is equal to the force of gravity acting on each of them individually.
So the drag force on the heavier body is greater than the drag force on the lighter body. During this condition the bodies fall with a uniform velocity called terminal velocity.
where:
density of the air
A= area normal to the direction of fall
v= terminal velocity
coefficient of drag
Answer:
The independent variable is plotted on the x-axis. This is the variable that is being manipulated or controlled.
C Not enough information,not clear on what you are asking for