Answer:
Answer:
43.4J
Explanation:
We know that
Work done = total heat energy
But work done is force x distance
=> F = 19 x8.6 = 163.4 J
So the total heat. Will be Heat of cube + heat of floor = 163.4J
So that heat of floor will now be
floor = 163.4 J - 120 J = 43.4 Joules
Explanation:
Answer:
Distance, d = 0.049 meters
Explanation:
It is given that,
Mass of the pile, m = 2500 kg
It is dropped through a height of 8.0 m on each stroke, h = 8 m
The resisting force of the ground,
The work done in each stroke is equal to the potential energy of the pile driver such that,
Work done due to resistive force is :
So,
d is the distance covered by the post driven in on each stroke.
d = 0.049 meters
So, on each stroke the post driven is 0.049 meters far. Hence, this is the required solution.
Answer:
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Answer
given,
Distance for decibel reading
r₁ = 13 m
r₂ = 24 m
When the engineer is at r₁ reading is β₁ = 101 dB
now, Calculating the Intensity at r₁
Using formula
I₀ = 10⁻¹² W/m²
now inserting the given values
I = 0.01258 W/m²
now, calculating power at r₁
P₁ = I₁ A₁
P₁ = 0.01258 x 4 π r²
P₁ = 0.01258 x 4 π x 13²
P₁ = 26.72 W
Answer:
A)Explanation:
Let object distance be u.
Image distance v = 1.06 - u
Focal length = 20 cm = .2 m
Applying lens formula
1 / v - 1 / u = 1 / f
1 /( 1.06-u) - 1 / u = 1 / .2
5 u² -3.3u - 1.06 =0
It will have two roots
u₁ = .1636 m, u₂ = .8964 m
B ) Magnification
= u = .1636m , v = .8964m
m = .8964 / .1636 = 5.48
C ) When u = .8964m ,v = .1634m
m = .1634 / .8964
=.182