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Paha777 [63]
3 years ago
5

Name the algebraic property demonstrated in the example below:. 2 + x + y = x + 2 + y. A) Commutative Property of Addition. B) A

ssociative Property of Addition. C) Reflexive Property. D) Transitive Property
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
6 0
The answer is A) commutative property of addition
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The answer is 8 to 1 because divide 36to4 that equals 8 then4 divide to 4 its 1
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A. Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is
Furkat [3]

Answer:

y  =  2 -  ( x - 1)²/9

Step-by-step explanation: See Annex

As the parameter t increases,  the value of x increases and the value of y decreases, we get the figure of the annex ( the arrow in the Annex indicates the way of the curve with t increasing.

b) to eliminate the parameter:

x  =  1  + 3*t    (1)          y  =  2  -  t²  (2)

Then  from equation (1)  t  = ( x  - 1 ) / 3

plugging that value in equation (2)

y  =  2  -  [ (  x  -  1 ) / 3 ]²

y  =  2  - ( x² + 1 - 2*x)/9

9*y  =  18  - x² + 1 - 2*x    or    y  =  2 -  ( x - 1)²/9

The curve is a parabol

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5 0
3 years ago
How do I do the pattern
lilavasa [31]
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What are the roots of x in -10x2 + 12x − 9 = 0?
hoa [83]

Answer:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

Step-by-step explanation:

Use the Quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

You can identify that, in this case:

a=-10\\b=12\\c=-9

Now you need to substitute these values into the formula:

x=\frac{-12\±\sqrt{12^2-4(-10)(-9)}}{2(-10)}

x=\frac{-12\±\sqrt{-216}}{-20}

Remember that:

i=\sqrt{-1}

Therefore,rewriting and simplifying, you get:

x=\frac{-12\±6i\sqrt{6}}{-20}

x=\frac{-6(2\±i\sqrt{6})}{-2(10)}

x=\frac{3(2\±i\sqrt{6})}{10}

Then, you get the following roots:

x_1=\frac{3(2+i\sqrt{6})}{10}

x_2=\frac{3(2-i\sqrt{6})}{10}

6 0
2 years ago
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Step-by-step explanation:

\frac{ {x}^{3} }{ {x}^{3} }  =   {x}^{3 - 3}  \\  =  {x}^{0}  \\  = 1

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