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2 years ago

I need to solve x pls

Mathematics

1 answer:

Marat540 [252]2 years ago

8 0

Answer:

I think x is 38 but it depend on how to solve it

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Reference angle for -19pi/6?

kow [346]

$\bf \cfrac{19}{6}\implies 3+\cfrac{1}{6}
\\ \quad \\\\
\cfrac{-19\pi }{6}\implies -\left(3\pi +\cfrac{1\pi }{6} \right)\impliedby clockwise
\\ \quad \\\\
or\implies -\left(2\pi +\pi +\cfrac{\pi }{6} \right)$

go that much "clockwise", you'll end up at the 2nd quadrant,
the reference angle, is its reflective angle on the 1st quadrant

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3 years ago

Asap help plz Decrease 1). 400 by 10% 2). 380 by 10% 3). 140 by 15% 4). 35 by 20%.

Varvara68 [4.7K]

1)360 (400*.9)
2)342 (380*.9)
3)119 (140*.85)
4)28 (35*.8)

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3 years ago

Thirty-six people auditioned for a play, and 6 people got roles. write the ratio in simplest form of the number of people who au

Mandarinka [93]

The ratio would be 6:1 because out of every 6 people, 1 person got a role. Please mark Brainliest!!!

3 0

3 years ago

Read 2 more answers

Solve for x<br> I don't know what to do with the parenthesis

irinina [24]

Answer:

x=21

Step-by-step explanation:

Notice the right angle. Perpendicular to it on the right, we have two complementary angles, 25, and 3x+2 (you can ignore the parentheses basically). Because they are complementary angles, they will add up to 90, so we can make an equation to solve for x:

25+3x+2=90

3x+2=65

3x=63

x=21

So x=21 is the correct answer. Let me know if you have any questions about my explanation.

6 0

3 years ago

If the diameter of a youth baseball is 2. 8 inches and the diameter of an adult softball is 3. 8 inches, what is the approximate

Molodets [167]

The approximate difference in their volumes is 17.2 cubic inches

<h3>How to determine the difference in the volume?</h3>

The given parameters are:

Diameter, d = 2.8

Diameter, D = 3.8

The radii are the half of the diameter.

So, we have:

r = 1.4

R = 1.9

The volume of the balls is then calculated using:

$V = \frac{4}{3}\pi r^3$

The difference is then represented as:

$D = \frac{4}{3}\pi (R^3 - r^3)$

Substitute known values

$D = \frac{4}{3}* 3.14* (1.9^3 - 1.4^3)$

Evaluate

D = 17.2

Hence, the approximate difference in their volumes is 17.2 cubic inches