Question

(10 pts+Brainliest) SOLVE PLS the geometric proof below. Given: ∠WXT≅∠XWY, ∠XWT≅∠WXY Prove: ΔTWX≅ΔYXW

Answer 1

One way to prove this is to use a 2 column table like so

$\begin{array}{|l|l|} \cline{1-2} & \\\ \ \ \ \ \ \ \text{Statement} & \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Reason}\\ & \\\cline{1-2} & \\1. \ \angle WXT \cong \angle XWY & 1.\ \ \text{Given}\\ & \\\cline{1-2} & \\2.\ \angle XWT \cong \angle WXY & 2.\ \ \text{Given}\\ & \\\cline{1-2} & \\3.\ \overline{WX} \cong \overline{WX} & 3.\ \ \text{Reflexive Property}\\ & \\\cline{1-2} & \\4. \ \triangle TWX \cong \triangle YXW & 4.\ \ \text{ASA Congruence Theorem}\\ & \\\cline{1-2}\end{array}$

The first two statements are literal word-for-word repeats of what your teacher mentioned. This is how every proof starts off. It seems silly to repeat things, but that's just how it is. The goal is to connect what you're given to what you want to prove.

We'll involve the reflexive property in statement 3 so that we can use ASA (angle side angle) in statement 4. Notice how statements 1 & 2 handle the "angle" part of ASA, while statement 3 handles the "side" of ASA. The sides mentioned are between the angles mentioned.