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vaieri [72.5K]
2 years ago
5

Describe the parts of this algebraic expression using the lesson’s vocabulary. Negative x + 10.2 minus one-half x + y

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
7 0

The equation would be -x+10.2-\frac{1}{2}x+y

The equation contains:

-decimals

-variables

-negatives

-fractions

-like-terms

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***<br> -6<br> Simplify 21v6 ÷ (-7v-6)<br> O 0<br> -3y¹2<br> -3<br> 12<br> 0 -3<br> DONE<br> 0 0
-Dominant- [34]

Answer:

-3

Step-by-step explanation:

\frac{  21y {}^{ - 6} }{ - 7y {}^{ - 6} }  \\  - 3y {}^{ - 6 - ( - 6)}  \\  - 3y {}^{ - 6 + 6}  \\  - 3y {}^{0}  \\  - 3(1) \\  - 3

3 0
2 years ago
CAN SOMEONE PLEASE HELP ME!!!!!
USPshnik [31]

Answer:

Step-by-step explanation:

2{5x²-15+(-9xy²)}-(2y²+4x-xy²)+3x²

=2{5x²-15-9xy²}-(2y²+4x-xy²)+3x²

=10x²-30-18xy²-2y²-4x+xy²+3x²

=13x²-2y²-17xy²-4x-30

8 0
3 years ago
Please solve with explanation
OverLord2011 [107]

Real life scenarios of acute angles are:

  • Sighting a ball from the top of a building at an angle of 55 degrees.
  • The angle between two adjacent vanes of a fan that has 6 vanes

<h3>What are acute angles?</h3>

As a general rule, an acute angle, x is represented as: x < 90

This means that acute angles are less than 90 degrees.

<h3>The real life scenarios</h3>

The real life scenarios that involve acute angles are scenarios that whose measure of angle is less than 90 degrees.

Sample of the real life scenarios that satisfy the above definition are:

  • Sighting a ball from the top of a building at an angle of 55 degrees.
  • The angle between two adjacent vanes of a fan that has 6 vanes

Read more about acute angles at:

brainly.com/question/3217512

#SPJ1

8 0
2 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
faltersainse [42]

Answer:

V = 34,13*π   cubic units

Step-by-step explanation: See Annex

We find the common points of the two curves, solving the system of equations:

y²  = 2*x                           x = 2*y  ⇒  y = x/2

(x/2)² = 2*x

x²/4 = 2*x

x  =  2*4         x  = 8      and   y = 8/2       y = 4

Then point  P ( 8 ;  4 )

The other point Q is  Q ( 0; 0)

From these  two points, we get the integration limits for dy ( 0 , 4 )are the integration limits.

Now with the help of geogebra we have: In the annex segment ABCD is dy then

V = π *∫₀⁴ (R² - r² ) *dy   =  π *∫₀⁴ (2*y)² - (y²/2)² dy =  π * ∫₀⁴ [(4y²) - y⁴/4 ] dy

V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴

V =  π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )

V = π * [256/3  - 51,20]

V = 34,13*π   cubic units

3 0
3 years ago
The length of a rectangle is 3 inches longer then twice its width, where w is the width of the rectangle the area of the rectang
vaieri [72.5K]
A = w(2w + 3)
90 = 2w^2 + 3w
2w^2 +3w - 90 = 0
(w-6)(2w+15) = 0        (TRINOMIAL FACTORING)
w = 6 inch                   ( it can't be -15/2 because lengths can't be negative)
l = 2w + 3
  = 15 inch
6 0
3 years ago
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